第三天、计算某日是该年的第几天

/*第三天、计算某日是该年的第几天*/
#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    /*参数依次为年、月、日、计算天数、for循环初始值*/
    /*注意：days赋初始值0，不赋值，变量的值不确定，会导致运行崩溃*/
    int year,month,day,days = 0,i = 0;
    int average_year[12] = {31,28,31,30,31,30,31,31,30,31,30,31};    //平年
    int leap_year[12] = {31,29,31,30,31,30,31,31,30,31,30,31};        //闰年
    printf("请输入要查询的日期，例如：1993年1月30日\n");
    scanf("%d年%d月%d日",&year,&month,&day);
    /*能被400整除，或者不能被100整除但能被4整出的年份为闰年*/
    if(year % 400 == 0 || year % 4 == 0 && year % 100 != 0)                        
    {
        /*数组的第一个元素的索引值为0，将month月的前几个月相加*/
        for(i;i <= month - 2;i++)
            days += leap_year[i];
        /*将month月的day天加上，为最终的天数*/
        days += day;
    }
    else        /*不满足，则为平年*/
    {
        /*同上*/
        for(i;i <= month - 2;i++)
            days += average_year[i];
        days += day;
    }
    printf("%d年%d月%d日是%d年的第%d天\n",year,month,day,year,days);
    system("pause");
}

def leap(a):
    if (a % 4 == 0) & (a % 100 != 0) | (a % 400 == 0):
        return 1
    else:
        return 0

def number(y,m,d):
    result = 0
    average_year = (31,28,31,30,31,30,31,31,30,31,30,31)    #平年的元组
    leap_year = (31,29,31,30,31,30,31,31,30,31,30,31)       #闰年的元组
    if (1 <= y <= 5000) & (1 <= m <= 12) & (1 <= d <=31) & leap(y) & (d <= leap_year[m-1]):
        for i in range(0,m-1):
            result += leap_year[i]
    elif (1 <= y <= 5000) & (1 <= m <= 12) & (1 <= d <=31) & (leap(y) == 0) & (d <= average_year[m-1]):
        for i in range(0,m-1):
            result += average_year[i]
    else:
        result = 0
        d = 0
    result += d
    return result

def tranform(contents):
    if ('年' in contents) & ('月'in contents) & ('日' in contents) & (' ' not in contents):
        str_len = len(contents)
        for i in range(1,str_len):
            if contents[i] == '年':
                year = int(contents[0:i])       #input()接收的是字符串
                year_num = i + 1
            if contents[i] == '月':
                month = int(contents[year_num:i]) #用int()强制转换成整型
                month_num = i + 1
            if contents[i] == '日':  
                day = int(contents[month_num:i])
        return (year,month,day)
    else:
        return 0

choose = 1    
while choose:            
    contents = input('请输入要查询的日期，查询范围公元1年-公元5000年，例如：1993年1月30日\n')
    t = tranform(contents)
    if t != 0:
        result = number(t[0],t[1],t[2])
        if result != 0:
            print('第%d天' %(result))
            while True:
                choose = input('输入‘是’继续查询，输入‘否’放弃查询\n')
                if ('是' in choose) | ('否' in choose) & (len(choose) == 1):
                    if '是' in choose:
                        choose = 1
                        break
                    else:
                        choose = 0
                        break
                else:
                    print('输入选择错误，请重新输入\n')
        else:
            print('输入日期错误，请重新输入\n')
    else:
        print('输入格式错误，请重新输入\n')