ACM模版
签到题,二分即可。
#include <iostream>
#include <cstdio>
using namespace std;
typedef long long ll;
ll n;
int main()
{
int T;
cin >> T;
for (int ce = 1; ce <= T; ce++)
{
scanf("%lld", &n);
ll l = 0, r = 2e9, m, sum, ans = 0;
while (l <= r)
{
m = (l + r) >> 1;
sum = (1 + m) * m / 2;
if (sum <= n)
{
ans = sum;
l = m + 1;
}
else
{
r = m - 1;
}
}
printf("Case #%d: %lld\n", ce, ans);
}
return 0;
}