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社区首页 >专栏 >Leetcode 278. First Bad Version

Leetcode 278. First Bad Version

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triplebee
发布2018-01-12 14:35:33
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发布2018-01-12 14:35:33
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You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

1-n个版本,找出第一个出错的版本。

二分,但是一开始总是超时,想破头,最后发现 l + r会溢出int。

代码语言:javascript
复制
// Forward declaration of isBadVersion API.
bool isBadVersion(int version);

class Solution {
public:
    int firstBadVersion(int n) {
        long long l = 1, r = n;
        while(l <= r)
        {
            int mid = (l + r) >> 1;
            if(isBadVersion(mid)) r = mid - 1;
            else l = mid + 1;
        }
        return l;
    }
};
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原始发表:2017-04-16 ,如有侵权请联系 cloudcommunity@tencent.com 删除

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