前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >Leetcode 167 Two Sum II - Input array is sorted

Leetcode 167 Two Sum II - Input array is sorted

作者头像
triplebee
发布2018-01-12 14:48:13
5240
发布2018-01-12 14:48:13
举报

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9 Output: index1=1, index2=2

找出相加和为target的两个数。

非常简单,什么姿势都可以。

代码语言:javascript
复制
class Solution {
public:
    vector<int> twoSum(vector<int>& numbers, int target) {
        int l = 0, r = numbers.size()-1;
        vector<int> res;
        while(l <= r)
        {
            if(numbers[l] + numbers[r] == target)
            {
                res.push_back(l+1);
                res.push_back(r+1);
                break;
            }
            else if(numbers[l] + numbers[r] > target)
                r--;
            else
                l++;
        }
        return res;
    }
};
本文参与 腾讯云自媒体分享计划,分享自作者个人站点/博客。
原始发表:2017-01-09 ,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体分享计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档