Leetcode 58 Length of Last Word
Leetcode 58 Length of Last Word
triplebee
发布于 2018-01-12 15:04:09
发布于 2018-01-12 15:04:09
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
计算最后一个单词的长度
从后向前找第一个单词，注意处理后缀空格串！
class Solution {
public:
int lengthOfLastWord(string s) {
int result=0,flag=0;
for(int i=s.size()-1;i>=0;i--)
{
if(!flag && s[i]==' ') continue;
if(s[i]!=' ')
{
flag=1;
result++;
}
else
break;
}
return result;
}
};本文参与 腾讯云自媒体分享计划，分享自作者个人站点/博客。
原始发表：2016-09-19 ，如有侵权请联系 cloudcommunity@tencent.com 删除
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