Hdu 1025

#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
int dp[500005];
int map[500005];
int main()
{
    int n,i,j,k,cases=0;
    int len,up,low,mid;
    while(~scanf("%d",&n))
    {
		cases++;
        int a,b;
        for(i=0;i<n;i++)
        {
            scanf("%d%d",&a,&b);
            map[a]=b;
        }
        dp[1]=map[1];
        len=1;
        for(i=2;i<=n;i++)
        {
            low=1;
            up=len;
            while(low<=up)
            {
		mid=(up+low)/2;//一开始这条放在外面，死活T，二分不太熟悉，也是调了半天才发现
                if(dp[mid]<map[i])
                {
                    low=mid+1;
                }
                else
                {
                    up=mid-1;
                }
            }
            dp[low]=map[i];
            if(low>len)
            len++;
        }
		if(len==1)
			printf("Case %d:\nMy king, at most %d road can be built.\n\n",cases,len);//一条路和多条路不同没有s，其实仔细看题，题目也给出了
		else
			printf("Case %d:\nMy king, at most %d roads can be built.\n\n",cases,len);//每组样例间有回车符，最后结尾一定要有两个回车符
    }
    return 0;
}