【答疑解惑】将字符串中连续相等的字符合并

前段时间有小伙伴在弄字符串合并出了问题。写一段代码来解决这个问题

#include <stdio.h>

#include <string.h>

int ChangeString(char *inStr, char *outStr, int n)

{

int i = 0, j = 0;

if (inStr == NULL && outStr == NULL)

{

return -1;

}

int flag = 0;

char asc = 0xff;

int len = strlen(inStr);

if (len == 0)

*outStr = '\0';

while(inStr[i] != '\0')

{

if (asc == inStr[i])

flag++;

else {

if (flag >= (n - 1) && j > 1) {

j -= flag;

}

flag = 0;

}

asc = inStr[i];

outStr[j++] = inStr[i++];

}

if (flag >= (n - 1) && j > 1)

j -= flag;

outStr[j] = '\0';

return 0;

}

int main(int argc, char **argv)

{

char out[300] = {0};

printf("you input:%s\n", argv[1]);

if (!argv[1] || strlen(argv[1]) <= 0)

{

printf("you input is null!!!");

return 0;

}

int n = 3;

ChangeString(argv[1], out, n);

printf("out string = %s\n", out);

return 0;

}

n为有多少个相同的字符时合并。

执行：./test aaabbbb44rrrrddddfffffffffffffffff

执行结果：out string = ab44rdf