mysql、mongodb、python(dataframe).聚合函数的形式，以及报错解决方案

select * from table_name group by  name,id

select name,id,fenshu from table_name group by  name,id

db.collection.aggregate([ { $group: {"_id": { "adcode" : "$adcode", "typecode": "$typecode"} , "number":{$sum:1}} } ]) 

#!usr/bin/env python
#_*_ coding:utf-8 _*_
import pandas as pd

def handel_01():
    pd_data_01=pd.read_csv('C:\\Users\\lenovo\\Desktop\\weibo_V\\result\\weibo_pd_data1.csv',encoding='gbk')

    pd_data_01.groupby(['M_time','user_name'])['zhuanfa','dianzan','pinglun','v_text'].sum()
    print(pd_data_01)

if __name__=='__main__':
    handel_01()