题目连接 http://poj.org/problem?id=1330
就是构建一棵树,然后问你两个节点之间最近的公共父节点是谁?
代码:
1 /*Source Code
2 Problem: 1330 User: huifeidmeng
3 Memory: 1232K Time: 63MS
4 Language: C++ Result: Accepted
5
6 Source Code
7 */
8 #include<iostream>
9 #include<vector>
10 #include<cstdio>
11 #include<cstring>
12 #include<cstdlib>
13 using namespace std;
14 const int maxn=10002;
15 vector<int> tree[maxn],qus[maxn];
16 int rank[maxn],father[maxn];
17 bool vis[maxn];
18 int rudu[maxn];
19 int lroot[maxn];
20 void init(int n){
21 memset(vis,0,sizeof(vis));
22 memset(rudu,0,sizeof(rudu));
23 memset(lroot,0,sizeof(lroot));
24 for(int i=1;i<=n;i++){
25 father[i]=i;
26 rank[i]=1;
27 tree[i].clear();
28 qus[i].clear();
29 }
30 }
31 int find(int a){
32 while(a!=father[a])
33 a=father[a];
34 return a;
35 }
36 void Union(int a,int b)
37 {
38 int x=find(a);
39 int y=find(b);
40 if(x==y) return ;
41 if(rank[x]<rank[y]){
42 rank[y]+=rank[x];
43 father[x]=y;
44 }
45 else {
46 rank[x]+=rank[y];
47 father[y]=x;
48 }
49 }
50 void LCA(int u)
51 {
52 lroot[u]=u;
53 int len=tree[u].size();
54 for(int i=0;i<len;i++){
55 LCA(tree[u][i]);
56 Union(u,tree[u][i]);
57 lroot[find(u)]=u;
58 }
59 vis[u]=1;
60 int ss=qus[u].size();
61 for(int i=0;i<ss;i++){
62 if(vis[qus[u][i]]){
63 printf("%d\n",lroot[find(qus[u][i])]);
64 return ;
65 }
66 }
67 }
68 int main()
69 {
70 int cas,n,u1,u2;
71 //freopen("test.in","r",stdin);
72 scanf("%d",&cas);
73 while(cas--){
74 scanf("%d",&n);
75 init(n);
76 for(int i=1;i<n;i++){
77 scanf("%d%d",&u1,&u2);
78 tree[u1].push_back(u2);
79 rudu[u2]++;
80 }
81 scanf("%d%d",&u1,&u2);
82 qus[u1].push_back(u2);
83 qus[u2].push_back(u1);
84 for(int i=1;i<=n;i++){
85 if(0==rudu[i]){ //找到root
86 LCA(i);
87 break;
88 }
89 }
90 }
91 return 0;
92 }