27:级数求和

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2

 1 ude<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #include<cmath>
 5 using namespace std;
 6 int main()
 7 {
 8     int n;
 9     cin>>n;
10     double tot=0;
11     double fm=1;
12     for(int i=1;i<=999999;i++)
13     {
14         tot=tot+(1/fm);
15         if(tot>n)
16         {
17         cout<<fm;
18         break;
19         }
20             fm++;
21     }
22     return 0;
23 }