51 Nod 1057 N的阶乘【Java大数乱搞】

输入N(1 <= N <= 10000)

输出N的阶乘

5

120

 1 import java.math.BigInteger;
 2 import java.util.Scanner;
 3 
 4 
 5 public class sss {
 6 
 7     /**
 8      * @param args
 9      */
10     public static void main(String[] args) {
11         // TODO Auto-generated method stub
12         Scanner in=new Scanner(System.in);
13         BigInteger sum=BigInteger.ONE;
14         int n;
15         n=in.nextInt();
16         for(int i=1;i<=n;i++)
17             sum=sum.multiply(BigInteger.valueOf(i));
18         System.out.println(sum);
19     }
20 }