import requests
class TestAssert():
def test_assert(self):
r = requests.get('http://www.baidu.com')
assert r.status_code == 100, "返回200说明访问成功"
# is_leap_year.py
def is_leap_year(year):
# 先判断year是不是整型
if isinstance(year, int) is not True:
raise TypeError("传入的参数不是整数")
elif year == 0:
raise ValueError("公元元年是从公元一年开始!!")
elif abs(year) != year:
raise ValueError("传入的参数不是正整数")
elif (year % 4 ==0 and year % 100 != 0) or year % 400 == 0:
print("%d年是闰年" % year)
return True
else:
print("%d年不是闰年" % year)
return False
import sys
sys.path.append(".")
import requests
import pytest
import is_leap_year
class TestAssert():
# 对一个判断是否是闰年的方法进行测试
def test_exception_typeerror(self):
with pytest.raises(TypeError):
is_leap_year.is_leap_year('ss')
def test_true(self):
assert is_leap_year.is_leap_year(400) == True
运行结果:
PS E:\python_interface_test\requests_practice> pytest -q .\test_assert.py.. [100%]2 passed in 0.31 seconds
import sys
sys.path.append(".")
import requests
import pytest
import is_leap_year
class TestAssert():
def test_exception_value(self):
with pytest.raises(ValueError) as excinfo:
is_leap_year.is_leap_year(0)
assert "从公元一年开始" in str(excinfo.value)
assert excinfo.type == ValueError
import sys
sys.path.append(".")
import requests
import pytest
import is_leap_year
class TestAssert():
def test_exception_match(self):
with pytest.raises(ValueError, match=r'公元33元年是从公元一年开始') as excinfo:
is_leap_year.is_leap_year(0)
assert excinfo.type == ValueError
运行结果:
将match中的Pattern该为能够匹配的信息,则该用例能够执行成功。
pytest.mark.xfail(raises=xx)
import sys
sys.path.append(".")
import requests
import pytest
import is_leap_year
class TestAssert():
@pytest.mark.xfail(raises=ValueError)
def test_a(self):
is_leap_year.is_leap_year(-100)
输出结果:
pytest的断言方式非常简洁明确。本节主要介绍了对异常信息的断言,包括4种情况:
作者: 乐大爷 博客:https://www.jianshu.com/u/39cef8a56bf9 声明:本文已获作者授权转载,著作权归作者所有。