package LinkedList;
import java.util.HashMap;
/**
* 两个链表的第一个公共结点
* 输入两个链表,找出它们的第一个公共结点。
*/
public class Solution22 {
public ListNode FindFirstCommonNode_2(ListNode pHead1, ListNode pHead2) {
if (pHead1 == null || pHead2 == null)
return null;
ListNode current1 = pHead1;
ListNode current2 = pHead2;
int length1 = getLength(current1);
int length2 = getLength(current2);
//如果链表1的长度大于链表2的长度
if (length1 >= length2) {
int len = length1 - length2;
//先遍历链表1,再遍历链表2,遍历的长度为两链表长度差
while (len > 0) {
current1 = current1.next;
len--;
}
} else {//如果链表2的长度大于链表1的长度
int len = length2 - length1;
//先遍历链表2,再遍历链表1,遍历的长度为两链表长度差
while (len > 0) {
current2 = current2.next;
len--;
}
}
//遍历剩下节点,直到找到第一个公共节点
while (current1 != current2) {
current1 = current1.next;
current2 = current2.next;
}
return current1;
}
/**
* 获取链表长度
*
* @param listNode
* @return
*/
private int getLength(ListNode listNode) {
int length = 0;
while (listNode != null) {
length++;
listNode = listNode.next;
}
return length;
}
/**
* 先把pHead1放入HashMap中
* 根据HashMap的containsKey方法,查询是否有相同的节点
*
* @param pHead1
* @param pHead2
* @return
*/
public ListNode FindFirstCommonNode(ListNode pHead1, ListNode pHead2) {
ListNode current1 = pHead1;
ListNode current2 = pHead2;
HashMap<ListNode, Integer> hashMap = new HashMap<>();
while (current1 != null) {
hashMap.put(current1, null);
current1 = current1.next;
}
while (current2 != null) {
if (hashMap.containsKey(current2)) {
return current2;
}
current2 = current2.next;
}
return null;
}
public class ListNode {
int val;
ListNode next = null;
ListNode(int val) {
this.val = val;
}
}
}