根据用户生日,得到相应的年龄,星座和生肖。有的项目中可能会用到,贴出来共享。
得到年龄,这个很简单了:
- (void)getAgeWith:(NSDate*)birthday{
//日历
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
NSUInteger unitFlags = NSCalendarUnitYear;
NSDateComponents *components = [gregorian components:unitFlags fromDate:birthday toDate:[NSDate date] options:0];
self.age.text = [NSString stringWithFormat:@"%ld岁了",[components year]+1];
}
根据月日得到星座:
//得到星座的算法
-(NSString *)getAstroWithMonth:(NSInteger)m day:(NSInteger)d{
NSString *astroString = @"魔羯水瓶双鱼白羊金牛双子巨蟹狮子处女天秤天蝎射手魔羯";
NSString *astroFormat = @"102123444543";
NSString *result;
if (m<1||m>12||d<1||d>31){
return @"错误日期格式!";
}
if(m==2 && d>29)
{
return @"错误日期格式!!";
}else if(m==4 || m==6 || m==9 || m==11) {
if (d>30) {
return @"错误日期格式!!!";
}
}
result=[NSString stringWithFormat:@"%@",[astroString substringWithRange:NSMakeRange(m*2-(d < [[astroFormat substringWithRange:NSMakeRange((m-1), 1)] intValue] - (-19))*2,2)]];
return [result stringByAppendingString:@"座"];
}
根据年份得到生肖:
-(NSString *)getZodiacWithYear:(NSInteger)y{
if (y <0) {
return @"错误日期格式!!!";
}
NSString *zodiacString = @"鼠牛虎兔龙蛇马羊猴鸡狗猪";
NSRange range = NSMakeRange ((y+9)%12-1, 1);
NSString* result = [zodiacString substringWithRange:range];
return [result stringByAppendingString:@"年"];
}
写了一个demo,需要的去这里下载:https://github.com/wangdachui/WTZodiacSigns