LinkedHashMap的accessOrder

    @Test
    public void fun2() throws Exception {
        LinkedHashMap<String, String> accessOrderTrue = new LinkedHashMap<>(16, 0.75f, true);
        accessOrderTrue.put("1","1");
        accessOrderTrue.put("2","2");
        accessOrderTrue.put("3","3");
        accessOrderTrue.put("4","4");
        System.out.println("acessOrderTure"+accessOrderTrue);
        accessOrderTrue.get("2");
        accessOrderTrue.get("3");
        System.out.println("获取了数据"+accessOrderTrue);
    }
    //控制台输出
    acessOrderTure{1=1, 2=2, 3=3, 4=4}
    获取了数据{1=1, 4=4, 2=2, 3=3}