// ConsoleApplication4.cpp : 定义控制台应用程序的入口点。
//
#include "stdafx.h"
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<time.h>
#include<Windows.h>
/********函数变量声明********/
#define PR_Box printf("■")
#define PR_Gold printf("★")
#define PR_Ag printf("☆")
#define PR_FBird printf("Ю")
#define PR_DBird printf("Ф")
#define PR_Land printf("┳┳┯")
#define PR_Bg_TL printf("╔")
#define PR_Bg_TR printf("╗")
#define PR_Bg_DL printf("╚")
#define PR_Bg_DR printf("╝")
#define PR_Bg_X printf("═")
#define PR_Bg_Y printf("║")
#define PR_Blank printf(" ");
int Grade = 1, C_Gold = 0, C_Ag = 0, Score = 0, Delay_time = 1000, Max_blank = 9, Distance = 18;
//Grade 游戏等级
//Score 分数
//Max_blank 上下两个烟囱之间的最大距离
//Distance 左右两个烟囱之间的距离
struct Birds//小鸟的结构体
{
int x, y;//小鸟的位置
int condition;//此变量未用
};
Birds *Bird = (Birds*)malloc(sizeof(Birds));//给小鸟指针分配空间
struct Bg//烟囱的结构体--循环双向链表
{
int x, y;//上烟囱的左下角砖块的坐标
int l_blank;//上相两个烟囱之间的距离
int reward[9];
Bg *pri;//前指针-指向前一个结点
Bg *next;//后指针-指向后一个结点
};
Bg *Bg1 = new Bg[sizeof(Bg)];//将一个烟囱结点设置成全局变量
void Position(int x, int y)//将光标移动到X,Y坐标处
{
COORD pos = { x - 1, y - 1 };
HANDLE Out = GetStdHandle(STD_OUTPUT_HANDLE);
SetConsoleCursorPosition(Out, pos);
}
void CreatBird()//创建小鸟
{
Bird->x = 41;//小鸟的坐标
Bird->y = 10;
Bird->condition = 0;
}
void CreatBg()//创建数据结构为循环双向链表的烟囱
{
Bg *Bg2 = (Bg*)malloc(sizeof(Bg));
Bg1->x = 90; Bg1->y = 8;
Bg2->x = Bg1->x + Distance; Bg2->y = 9;
Bg1->l_blank = Max_blank - Grade;
Bg2->l_blank = Max_blank - Grade;
Bg1->next = Bg2;
Bg1->pri = Bg2;
Bg2->next = Bg1;
Bg2->pri = Bg1;
}
void InsertBg(Bg *p)//创建一个结点插入到传入结点之前。循环双向链表的插入
{
int temp;
Bg *Bgs = (Bg*)malloc(sizeof(Bg));
Bgs->x = p->pri->x + Distance;
Bgs->l_blank = Max_blank - Grade;
srand((int)time(0));//将系统时间作为产生随机数的种子
temp = rand();//产生随机数
if (temp % 2 == 0)//当随机数%==2时,烟囱口向下移动
{
if ((temp % 4 + p->pri->y + Max_blank - Grade)<21)//检测是否存在向下移动的可行性
Bgs->y = p->pri->y + temp % 4;//若有则向下移动temp%4个单位
else
Bgs->y = p->pri->y;//若无,则不动
}
else//反之亦然
{
if ((p->pri->y - temp % 4)>2)
Bgs->y = p->pri->y - temp % 4;
else
Bgs->y = p->pri->y;
}
Bgs->pri = p->pri;//循环链表指向
Bgs->next = p;
p->pri->next = Bgs;
p->pri = Bgs;
}
void Check_Bg(Bg *q)//检查是否有烟囱超出屏幕,若有超出,则移动到屏幕右侧。
{
Bg *p = q; int i = 0, temp;
while (++i <= 5)//注意烟囱只有5个,时来回循环移动的
{
if (p->x>-4)//若有烟囱超出
p = p->next;
else
{
srand((int)time(0));
temp = rand();
if (temp % 2 == 0)//++
{
if ((temp % 4 + p->y + Max_blank - Grade)<21)
p->y = p->y + temp % 4;
else
p->y = p->y;
p->x = p->pri->x + Distance;//将烟囱移动到前一结点的右侧+Distance的单位
p->l_blank = Max_blank - Grade;//计算上下两个烟囱的距离
}
else//反之亦然
{
if ((p->y - temp % 4)>2)
p->y = p->y - temp % 4;
else
p->y = p->y;
p->x = p->pri->x + Distance;
p->l_blank = Max_blank - Grade;
}
}
}
}
void Loop_Bg(Bg *q)//烟囱单向循环移动
{
Bg *p = q; int i = 0;
while (++i <= 5)
{
p->x = p->x - 1;
p = p->next;
if (Bird->x == p->x)//每经过一个烟囱,加一分
{
Score += 1;
if (Score % 4 == 0 && Grade<4)//烟囱
Grade++;
}
}
}
void Prt_Bg(Bg *q)//画烟囱----较冗余的代码
{
Bg *p = q; int i = 0, k, j;
while (++i <= 5)
{
if (p->x>0 && p->x <= 78)
{
for (k = 2; k<p->y; k++)//画出上烟囱上半部分
{
Position(p->x + 1, k);
PR_Box; PR_Box; PR_Blank;//输出两个格子,输出空格,清除原来余影
}
Position(p->x, p->y);//画出上烟囱下半部分
PR_Box; PR_Box; PR_Box; PR_Blank;//输出三个格子,输出空格,清除原来余影
Position(p->x, p->y + p->l_blank);//画出下烟囱上半部分
PR_Box; PR_Box; PR_Box; PR_Blank;//输出三个格子,输出空格,清除原来余影
k = k + p->l_blank + 1;
for (k; k <= 22; k++)//画出下烟囱下半部分
{
Position(p->x + 1, k);
PR_Box; PR_Box; PR_Blank;//输出两个格子,输出空格,清除原来余影
}
Position(p->x, 23);//输出地下的线
for (k = 1; k<Distance / 3 - 2; k++)
PR_Land;
}
p = p->next;
if (p->x == 0)
{
for (j = 2; j<p->y; j++)
{
Position(p->x + 1, j);
PR_Blank; PR_Blank;
}
Position(p->x + 1, p->y);
PR_Blank; PR_Blank; PR_Blank;
Position(p->x + 1, p->y + Max_blank - Grade);
PR_Blank; PR_Blank; PR_Blank;
j = j + Max_blank - Grade + 1;
for (j; j <= 22; j++)
{
Position(p->x + 1, j);
PR_Blank; PR_Blank;
}
}
}
}
void PrtBg()//画上下两条线
{
int i;
Position(1, 1); PR_Bg_TL;
Position(79, 1); PR_Bg_TR;
Position(1, 24); PR_Bg_DL;
Position(79, 24); PR_Bg_DR;
for (i = 3; i <= 78; i += 2)
{
Position(i, 1); PR_Bg_X;
Position(i, 24); PR_Bg_X;
}
/*for(i=2;i<=23;i++)
{ Position(1,i);PR_Bg_Y;printf("%d",i-1);
Position(79,i);PR_Bg_Y;
}*/
}
void PrtBird()//画鸟
{
Position(Bird->x, Bird->y - 1);//清除原来屏幕上面的鸟
PR_Blank;
Position(Bird->x, Bird->y);//画新鸟
PR_FBird;
Position(38, 2);
printf("Score:%d", Score);//输出得分
}
int CheckYN(Bg *q)//检查是否撞壁
{
Bg *p = q; int i = 0;
while (++i <= 5)
{
if (Bird->y>23)//鸟是否落地
return 0;
if (Bird->x == p->x&&Bird->y <= p->y)//是否撞到上烟囱左侧
return 0;
if ((Bird->x == p->x || Bird->x == p->x + 1 || Bird->x == p->x + 2) && Bird->y == p->y)//是否撞到上烟囱下侧
return 0;
if (Bird->x == p->x&&Bird->y>p->y + p->l_blank)//是否撞到下烟囱左侧
return 0;
if ((Bird->x == p->x || Bird->x == p->x + 1 || Bird->x == p->x + 2) && Bird->y == p->y + p->l_blank)//是否撞到上烟囱上侧
return 0;
p = p->next;
}
return 1;
}
void Prtfirst()
{
printf("══════════════════════════════════════\n");
printf(" ■■ ■■\n");
printf(" ■■ ■■\n");
printf(" ■■ ■■ C语言版 Flappy Bird\n");
printf(" ■■ ■■ 瞎搞人:yyposs\n");
printf(" ■■ ■■ 瞎搞日期:2014.2\n");
printf(" ■■ ■■ 耗时:4小时\n");
printf(" ■■■ ■■ 游戏说明:\n");
printf(" ■■ 1-按上箭头使鸟起飞\n");
printf(" ■■ 2-等级越高,难度越大!\n");
printf(" Ю ■■■\n");
printf("\n");
printf(" ■■■ 欢迎各路大神与我探讨C、C++、VB、PHP、C#\n");
printf(" ■■\n");
printf(" ■■\n");
printf(" ■■ ■■■ 【无版权,随意修改】\n");
printf(" ■■ ■■\n");
printf(" ■■ Ф ■■\n");
printf(" ■■ ■■\n");
printf(" ■■ ■■\n");
printf(" ■■ ■■\n");
printf(" ■■ ■■\n");
printf(" ┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳\n");
system("pause");
Position(1, 1);
int i = 0;
while (i++<40 * 25)
PR_Blank;
}
void main()
{
int i = 0; char ch;
Prtfirst();//开始屏幕
PrtBg();//画上下两边的框框
CreatBg();//创建循环双向链表烟囱
InsertBg(Bg1);//给循环双向链表中插入一个烟囱结点
InsertBg(Bg1);//给循环双向链表中插入一个烟囱结点
InsertBg(Bg1);//给循环双向链表中插入一个烟囱结点
CreatBird();//创造小鸟
while (1)
{
if (!CheckYN(Bg1))//检查鸟是否碰壁
break;//若碰壁,则退出
Check_Bg(Bg1);//检查是否有烟囱X坐标<0
Prt_Bg(Bg1);//画背景烟囱
PrtBird();//画小鸟
Loop_Bg(Bg1);//背景烟囱单项循环
Bird->y = Bird->y + 1;
if (GetAsyncKeyState(VK_UP))//检测是否有按键
{
Position(Bird->x, Bird->y - 1);
PR_Blank;//在屏幕上清除原小鸟
Bird->y = Bird->y - 4;//鸟的位置上升4个长度
}
while (i++<500);
{ Sleep(100);
}
i = 0;
}
Position(38, 10);
printf("You Lost!");
Position(1, 25);
system("pause");
}
// 1 2 3 4 5 6 7 8 10 15 20 25 30 35 38
//══════════════════════════════════════
//1 ■■ ■■
//2 ■■ ■■
//3 ■■ ■■
//4 ■■ ■■
//5 ■■ ■■
//6 ■■ ■■
//7 ■■■ ■■
//8 ■■
//9 ■■
//10 Ю ■■■
//11
//12 ■■■
//13 ■■
//14 ■■
//15 ■■ ■■■
//16 ■■ ■■
//17 ■■ Ф ■■
//18 ■■ ■■
//19 ■■ ■■
//20 ■■ ■■
//21 ■■ ■■
//22┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳
//══════════════════════════════════════