Python高效编程(二)

#可迭代对象
l = [1,2,3,4]
s = 'abcde'

#迭代器对象
t = iter(l)

import requests
from collections import Iterator,Iterable

#实现一个迭代器对象WeatherIterator,__next__方法每次返回一个城市气温
class WeatherIterator(Iterator):
    def __init__(self,cities):
        self.cities = cities
        self.index = 0
        
    def getWeather(city):
        r = requests.get(u'http://wthrcdn.etouch.cn/weather_mini?city=' + city)
        data = r.json()['data']['forecast'][0]
        return '%s: %s ,%s '%(city,data['low'],data['high'])

    def __next__(self):
        if self.index == len(self.cities):
            raise StopIteration
        city = self.cities[self.index]
        self.index += 1
        return getWeather(city)

#实现一个可迭代对象WeatherIterable,__iter__方法返回一个迭代器对象
class WeatherIterable(Iterable):
    def __init__(self,cities):
        self.cities = cities
        
    def __iter__(self):
        return WeatherIterator(self.cities)
    
#[u'漠河',u'海南',u'乌鲁木齐',u'上海']
for x in WeatherIterable([u'漠河',u'海南',u'乌鲁木齐',u'上海']):
    print(x)

# 给定一个可迭代对象的类,它能迭代出给定范围内的所有素数

class PrimeNumber():
    def __init__(self,start,end):
        self.start = start
        self.end = end
        
    def isPrimeNum(self,k):
        if k < 2:
            return False
        for i in range(2,k):
            if k % i == 0:
                return False
        return True
    
    def __iter__(self):
        for k in range(self.start,self.end + 1):
            if self.isPrimeNum(k):
                yield k

                
for x in PrimeNumber(1,100):
    print(x)

#实现一个连续浮点数发生器FloatRange(start,end,step)

# l = [1,2,3,4,5]

# for x in reversed(l):
#     print(x)

class FloatRange():
    def __init__(self,start,end,step=0.1):
        self.start = start
        self.end = end
        self.step = step
    
    def __iter__(self):
        t = self.start
        while t <= self.end:
            yield t
            t += self.step
            
    def __reversed__(self):
        t = self.end
        while t >= self.start:
            yield t
            t -= self.step


for x in reversed(FloatRange(1.0,5.5,0.5)):
    print(x)

#有一个文本文件,我们想获取某范围内的内容 eg:100-300lines

import this

f = open('test','w')
f.write(this.s)
f.close()

from itertools import islice

f = open('test','r')
for x in islice(f,3,5):
    print(x)

from random import randint

#每个学生有三门成绩(并行)
chese_grade = [randint(60,100) for _ in range(50)]
english_grade = [randint(60,100) for _ in range(50)]
math_grade = [randint(60,100) for _ in range(50)]

for c,e,m in zip(chese_grade,english_grade,math_grade):
    print('总分:%3d 语文:%3d 英语:%3d 数学:%3d'%(c+e+m,c,e,m))

#有四个班,一次英语考试的成绩存储在四个列表里,统计90以上的人数(串行)
from itertools import chain

chain([1,2,3,4],['a','b','c'])

english_grade1 = [randint(60,100) for _ in range(45)]
english_grade2 = [randint(60,100) for _ in range(53)]
english_grade3 = [randint(60,100) for _ in range(49)]
english_grade4 = [randint(60,100) for _ in range(35)]

count = 0

for x in chain(english_grade1,english_grade2,english_grade3,english_grade4):
    if x >= 90:
        count += 1

print(count)