PAT Basic 1002

#include<stdio.h>
char a[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
/*递归的从左至右输出各个位*/
void b(int sum,int count)
{
	count++;
	if(sum/10 !=0 )
		b(sum/10,count);
	if(count==1)
		printf("%s",a[sum%10]);
	else
		printf("%s ",a[sum%10]);
}

int main()
{
	char n[102];
	int i=0,sum=0,r=1;
	scanf("%s",n);
	while(n[i]!='\0')
		sum += n[i++]-48 ;
	b(sum,0);
	return 0;
}