前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >BZOJ3073: [Pa2011]Journeys(线段树优化建图 Dijkstra)

BZOJ3073: [Pa2011]Journeys(线段树优化建图 Dijkstra)

作者头像
attack
发布2018-08-09 16:27:03
2840
发布2018-08-09 16:27:03
举报

题意

Sol

代码语言:javascript
复制
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
#define Pair pair<int, int> 
#define MP(x, y) make_pair(x, y)
using namespace std;
const int MAXN = 300010, MAXM = 2500010;
inline int read() {
    char c = getchar(); int x = 0, f = 1;
    while(c < '0' || c > '9') {if(c == '-') f = -1; c = getchar();}
    while(c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar();
    return x * f;
}
int N, M, P, tot;
struct Edge {
    int u, v, w, nxt;
}E[MAXM << 3];
int head[MAXM], num = 0;
inline void AddEdge(int x, int y, int z) {E[num] = (Edge) {x, y, z, head[x]}; head[x] = num++;}
struct Node {
    int ls, rs, l, r;
}T[MAXM];
int ra, rb, pos[MAXM], vis[MAXM], dis[MAXM];
void Build(int &k, int ll, int rr, int opt) {
    k = ++tot;
    T[k].l = ll; T[k].r = rr; 
    if(ll == rr) {if(opt == 1) pos[ll] = k; return ;}
    int mid = (ll + rr) >> 1;
    Build(T[k].ls, ll, mid, opt); Build(T[k].rs, mid + 1, rr, opt);
    if(opt == 1) AddEdge(T[k].ls, k, 0), AddEdge(T[k].rs, k, 0);
    else AddEdge(k, T[k].ls, 0), AddEdge(k, T[k].rs, 0);
}
void AddLeaf(int k) {
    if(T[k].l == T[k].r) {AddEdge(k, pos[T[k].l], 0); return ;}
    AddLeaf(T[k].ls); AddLeaf(T[k].rs);
}
void TreeAdd(int k, int ll, int rr, int to, int opt) {
    if(ll <= T[k].l && T[k].r <= rr) {opt == 1 ? AddEdge(k, to, 0) : AddEdge(to, k, 0); return ;}
    int mid = (T[k].l + T[k].r) >> 1;
    if(ll <= mid) TreeAdd(T[k].ls, ll, rr, to, opt); 
    if(rr >  mid) TreeAdd(T[k].rs, ll, rr, to, opt);
}
 
void Dijstra() {
    memset(dis, 0x7f, sizeof(dis)); dis[pos[P]] = 0; 
    priority_queue<Pair> q; 
    q.push(MP(0, pos[P]));
    while(!q.empty()) {
        int p = q.top().second; q.pop();
        if(vis[p]) continue; vis[p] = 1;
        for(int i = head[p]; ~i; i = E[i].nxt) {
            int to = E[i].v;
            if(!vis[to] && (dis[to] > dis[p] + E[i].w)) 
                dis[to] = dis[p] + E[i].w, q.push(MP(-dis[to], to));
        }
    }
}
void Add(int a, int b, int c, int d) {
    int p1 = ++tot, p2 = ++tot;
    TreeAdd(ra, a, b, p1, 1); 
    AddEdge(p1, p2, 1);
    TreeAdd(rb, c, d, p2, 0);   
}
int main() {    
    memset(head, -1, sizeof(head));
    N = read(); M = read(); P = read();
    Build(ra, 1, N, 1); Build(rb, 1, N, 0); AddLeaf(rb);
    for(int i = 1; i <= M; i++) {
        int a = read(), b = read(), c = read(), d = read();
        Add(a, b, c, d); Add(c, d, a, b);
    }
    Dijstra();
    for(int i = 1; i <= N; i++) printf("%d\n", dis[pos[i]]);
    return 0;
}
/*
 
*/
本文参与 腾讯云自媒体分享计划,分享自作者个人站点/博客。
原始发表:2018-08-02 ,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体分享计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • 题意
  • Sol
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档