LintCode 乘积最大子序列代码

public class Solution {
    /**
     * @param nums: an array of integers
     * @return: an integer
     */
    public int maxProduct(int[] nums) {
        // write your code here
        int[] max = new int[nums.length];
        int[] min = new int[nums.length];
        
        min[0] = max[0] = nums[0];
        int result = nums[0];
        for (int i = 1; i < nums.length; i++) {
            //保持连续
            min[i] = max[i] = nums[i];
            if (nums[i] > 0) {
                max[i] = Math.max(max[i], max[i - 1] * nums[i]);
                min[i] = Math.min(min[i], min[i - 1] * nums[i]);
            } else if (nums[i] < 0) {
                max[i] = Math.max(max[i], min[i - 1] * nums[i]);
                min[i] = Math.min(min[i], max[i - 1] * nums[i]);
            }
            
            result = Math.max(result, max[i]);
        }
        
        return result;
    }
}