A石子列阵(快速幂取模)
第一个位置可以有m种选择,其他每个位置m-1种
#include<stdio.h>
#include<algorithm>
#include<cmath>
#include<iostream>
using namespace std;
const int mod = 1e9 + 7;
long long quick_power(long long a, long long n)
{
long long ans = 1;
while (n != 0)
{
if (n & 1)
{
ans = (ans * a) % mod;
}
a = (a * a) % mod;
n = n >> 1;
}
return ans;
}
int main()
{
int n, m;
while (scanf("%d%d", &n, &m) != EOF)
{
long long ans = m * quick_power(m - 1, n - 1)%mod;
printf("%lld\n", ans);
}
}
B并查集
除去第一个点之外找出最大的集合
#include <bits/stdc++.h>
using namespace std;
const int N=1e6+5;
int f[N],cnt[N];
int fa(int a)
{
return f[a]==a?a:f[a]=fa(f[a]);
}
int main()
{
int n,ans=0;
scanf("%d",&n);
for(int i=0;i<=n;i++)f[i]=i;
int x,y;
for(int i=0;i<n-1;i++)
{
scanf("%d %d",&x,&y);
if(x!=1&&y!=1)
x=fa(x),y=fa(y),f[x]=y;
}
for(int i=0;i<=n;i++)
++cnt[fa(i)];
for(int i=0;i<=n;i++)
ans=max(cnt[i],ans);
printf("%d\n",ans);
return 0;
}
C PH试纸(计数)
#include <bits/stdc++.h>
using namespace std;
const int N=1000005;
typedef pair<int,int> pii;
int R[N],B[N];
int main()
{
cin.tie(0); cout.tie(0);
std::ios::sync_with_stdio(0);
int n,m;
int r=0,b=0;
char to;
scanf("%d %d",&n,&m);
getchar();
for(int i=1;i<=n;i++)
{
scanf("%c",&to);
if(to=='R')
{
R[++r]=i;
}else {
B[++b]=i;
}
}
getchar();
int q;
for(int i=1;i<=m;i++)
{
scanf("%c %d",&to,&q);
getchar();
if(to=='R')
{
if(q>r)printf("-1\n");
else printf("%d\n",R[q]);
}else
{
if(q>b)printf("-1\n");
else printf("%d\n",B[q]);
}
}
return 0;
}
D 插排树(dfs)
#include<bits/stdc++.h>
using namespace std;
int book[50001],ans;
int visit[50001];
typedef pair<int,int> pill;
vector<pill> v[50001];
void dfs(int d,int va)
{
int size=v[d].size();
if(size==0){
ans=max(ans,va);
return;
}
for(int i=0;i<size;i++)
{
int fw=v[d][i].first;
dfs(fw,va+v[d][i].second);
}
}
int main()
{
int n,root;
scanf("%d",&n);
ans=0;
for(int i=1;i<=n;i++)visit[i]=0,book[i]=0,v[i].clear();
for(int i=0;i<n-1;i++)
{
int in,to,vi;
scanf("%d %d %d",&in,&to,&vi);
v[to].push_back(pill(in,vi));
book[in]=1;
}
for(int i=1;i<=n;i++)
{
if(book[i]==0)
{
root=i; break;
}
}
dfs(root,0);
printf("%d\n",ans);
return 0;
}
E 青蛙
#include <iostream>
#include <algorithm>
using namespace std;
int map[300][300];
int book[300];
int ans[300];
int sum = 999, m, n;
void dfs(int k, int total)
{
if (total >= sum)
return;
if(total>(m-k+sum))
return;
ans[k]=min(ans[k],total);
if (k == m)
{
sum = min(sum, total);
return;
}
for (int i = 1; i <= m; i++)
{
if (map[k][i] != 0 && book[i] == 0)
{
book[i] = 1;
if((total + map[k][i])<ans[i])
dfs(i,total + map[k][i]);
book[i] = 0;
}
}
}
int main()
{
int a, b;
scanf("%d%d", &m, &n);
sum=m;
for(int i=0;i<=m;i++)ans[i]=9999;
map[0][1]=1;
map[1][0]=1;
for (int i = 2; i < 240; i++)
{
map[i - 1][i] = 1;
map[i][i - 1] = 1;
}
for (int i = 0; i < n; i++)
{
scanf("%d%d", &a, &b);
map[a][b] = 1;
}
book[1] = 1;
dfs(1, 1);
printf("%d\n", sum);
return 0;
}
F
#include<cstdio>
#include<iostream>
#include<cstring>
using namespace std;
typedef long long ll;
const int N=50010,mo=19260817;
int f[N],n,m;
int main(){
cin>>n>>m;
f[0]=1;
for (int i=1;i<=n;i++){
int x;scanf("%d",&x);
for (int j=x;j<=m;j++){
f[j]+=f[j-x];
if (f[j]>mo)f[j]-=mo;
}
}
int ans=0;
for (int i=1;i<=m;i++)(ans+=f[i])%=mo;
cout<<ans<<endl;
}