描述
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26; Give you a letter x and a number y , you should output the result of y+f(x).
输入On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).输出for each case, you should the result of y+f(x) on a line样例输入
6
R 1
P 2
G 3
r 1
p 2
g 3
样例输出
19
18
10
-17
-14
-4
#include <iostream>
#include <string>
using namespace std;
int main()
{
int n;
int a,b;
char ch;
cin>>n;
while(n--)
{
cin>>ch;
cin>>a;
if(ch>=65 && ch<=90)
ch -=64;
else
ch = 96-ch;
b = a +ch;
cout<<b <<endl;
}
return 0;
}