LeetCode Add Two Numbers

丹

发布于 2018-09-04 11:38:08

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发布于 2018-09-04 11:38:08

文章被收录于专栏：WD学习记录

[LeetCode] 2. Add Two Numbers 两数相加 @python

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example:

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.

Solution：

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def addTwoNumbers(self, l1, l2):
        """
        :type l1: ListNode
        :type l2: ListNode
        :rtype: ListNode
        """
        tmp=ListNode(0)
        res=tmp
        flag=0
        while l1!=None or l2!=None:
            tt=0
            if l1!=None:
                tt+=l1.val
                l1=l1.next
            if l2!=None:
                tt+=l2.val
                l2=l2.next

            res.next=ListNode((tt+flag)%10)
            flag=(tt+flag)//10
            res=res.next
            
        if flag:
            res.next=ListNode(1)
        res=tmp.next
        return res

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原始发表：2018年08月04日，如有侵权请联系 cloudcommunity@tencent.com 删除

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