java map遍历、排序，根据value获取key

1 Map<String,String> map = new HashMap<String, String>();  
2 map.put("one","java");  
3 map.put("two","cn");  
4 map.put("three","love");  

1 for(String key:map.keySet()){  
2     System.out.println("key="+key+"and value=" +map.get(key));  
3 }  

1 Iterator<Map.Entry<String,String>> it = map.entrySet().iterator();  
2    while(it.hasNext()){  
3      Map.Entry<String,String> entry=it.next();  
4      System.out.println("key=" +entry.getKey() +" and value="+entry.getValue());  
5  }  

1 for(String v:map.values()){  
2       System.out.println("value= "+ v);  
3 }  

1 for(Map.Entry<String,String > entry:map.entrySet()){  
2       System.out.println("key=" +entry.getKey() +" and value="+entry.getValue());  
3 } 

 1 public class MapSortDemo {
 2 
 3     public static void main(String[] args) {
 4 
 5         Map<String, String> map = new TreeMap<String, String>();
 6 
 7         map.put("KFC", "kfc");
 8         map.put("WNBA", "wnba");
 9         map.put("NBA", "nba");
10         map.put("CBA", "cba");
11 
12         Map<String, String> resultMap = sortMapByKey(map);    //按Key进行排序
13 
14         for (Map.Entry<String, String> entry : resultMap.entrySet()) {
15             System.out.println(entry.getKey() + " " + entry.getValue());
16         }
17     }
18     
19     /**
20      * 使用 Map按key进行排序
21      * @param map
22      * @return
23      */
24     public static Map<String, String> sortMapByKey(Map<String, String> map) {
25         if (map == null || map.isEmpty()) {
26             return null;
27         }
28 
29         Map<String, String> sortMap = new TreeMap<String, String>(
30                 new MapKeyComparator());
31 
32         sortMap.putAll(map);
33 
34         return sortMap;
35     }
36 }
37 
38 
39 比较器类
40 
41 class MapKeyComparator implements Comparator<String>{
42 
43     @Override
44     public int compare(String str1, String str2) {
45         
46         return str1.compareTo(str2);
47     }
48 }

 1        //如果在Treemap里面想按照value进行排序，我们必须借助工具类Collections.sort(List,Comparator);
 2         TreeMap<String,Object> map2 = new TreeMap<String,Object>();
 3         map2.put("a","a");
 4         map2.put("b","cccccc");
 5         map2.put("c","bbbbb");
 6         map2.put("d","eeee");
 7         map2.put("e","dd");
 8         ArrayList<Map.Entry<String,Object>> list = new ArrayList<Map.Entry<String,Object>>(map2.entrySet());
 9         Collections.sort(list,new Comparator<Map.Entry<String,Object>>() {
10 
11             @Override
12             public int compare(Entry<String, Object> o1, Entry<String, Object> o2) {
13                 //变成按照value排列
14 //                return o2.getValue().toString().compareTo(o1.getValue().toString());
15                 //按照value的长度排序
16                 Integer o11 = o1.getValue().toString().length();
17                 Integer o22 = o2.getValue().toString().length();
18                 return o22.compareTo(o11);
19             }
20             
21         });
22         
23         for(Map.Entry<String,Object> l :list){
24             System.out.println(l.getKey()+":"+l.getValue());
25         }

 1     //根据map的value获取map的key  
 2     private static String getKey(Map<String,String> map,String value){  
 3         String key="";  
 4         for (Map.Entry<String, String> entry : map.entrySet()) {  
 5             if(value.equals(entry.getValue())){  
 6                 key=entry.getKey();  
 7             }  
 8         }  
 9         return key;  
10     }  

 1         //利用list取最大值
 2         List<Double> listmap = new ArrayList<Double>();
 3         for(String key:mapp.keySet()){
 4             listmap.add(mapp.get(key));
 5         }
 6         //取到最大值的value
 7         double valueMax = Collections.max(listmap);
 8         //根据map的value获取map的key  
 9         String emotionMax = "";  
10         for (Map.Entry<String, Double> entry : mapp.entrySet()) {  
11             if(valueMax == entry.getValue()){  
12                 emotionMax = entry.getKey();  //取到最大值的 value 对应的 key
13             }
14         }