在前一节,学习了如何自定义登录页,但是用户名、密码仍然是配置在xml中的,这样显然太非主流,本节将学习如何把用户名/密码/角色存储在db中,通过db来实现用户认证
一、项目结构
与前面的示例相比,因为要连接db,所以多出了一个spring-database.xml用来定义数据库连接,此外,为了演示登录用户权限不足的场景,加了一个页面403.jsp,用来统一显示权限不足的提示信息
二、数据库表结构(oracle环境)
1 create table T_USERS
2 (
3 d_username VARCHAR2(50) not null,
4 d_password VARCHAR2(60),
5 d_enabled NUMBER(1)
6 );
7 alter table T_USERS
8 add constraint PK_USERS_USERNAME primary key (D_USERNAME) ;
9
10 create table T_USER_ROLES
11 (
12 d_user_role_id NUMBER(10) not null,
13 d_username VARCHAR2(50),
14 d_role VARCHAR2(50)
15 );
16 alter table T_USER_ROLES
17 add constraint PK_USER_ROLES primary key (D_USER_ROLE_ID);
18 alter table T_USER_ROLES
19 add constraint IDX_UNI_ROLE_USERNAME unique (D_USERNAME, D_ROLE);
这里创建了二张表,一张用来保存用户名/密码,另一张用来保存用户所属的权限角色,表名和字段名无所谓,可以随便改,但是用户表中,必须要有"用户名/密码/帐号的有效状态"这三列信息,权限角色表必须要有“用户名/权限角色”这二列信息
再insert几条测试数据
1 insert into T_USERS (D_USERNAME, D_PASSWORD, D_ENABLED)
2 values ('YJMYZZ', '123456', 1);
3
4 insert into T_USERS (D_USERNAME, D_PASSWORD, D_ENABLED)
5 values ('MIKE', 'MIKE123', 1);
6
7 insert into T_USER_ROLES (D_USER_ROLE_ID, D_USERNAME, D_ROLE)
8 values (1, 'MIKE', 'POWER');
9
10 insert into T_USER_ROLES (D_USER_ROLE_ID, D_USERNAME, D_ROLE)
11 values (2, 'YJMYZZ', 'ADMIN');
12
13 insert into T_USER_ROLES (D_USER_ROLE_ID, D_USERNAME, D_ROLE)
14 values (3, 'YJMYZZ', 'POWER');
这里插入了二个用户YJMYZZ/MIKE,而且MIKE属于POWER组,YJMYZZ同时属于POWER\ADMIN二个权限组
三、spring-security.xml
1 <beans:beans xmlns="http://www.springframework.org/schema/security"
2 xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
3 xsi:schemaLocation="http://www.springframework.org/schema/beans
4 http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
5 http://www.springframework.org/schema/security
6 http://www.springframework.org/schema/security/spring-security-3.2.xsd">
7
8 <http auto-config="true" use-expressions="true">
9 <intercept-url pattern="/admin**" access="hasRole('ADMIN')" />
10 <!-- access denied page -->
11 <access-denied-handler error-page="/403" />
12 <form-login login-page="/login" default-target-url="/welcome"
13 authentication-failure-url="/login?error" username-parameter="username"
14 password-parameter="password" />
15 <logout logout-success-url="/login?logout" />
16 <!-- enable csrf protection -->
17 <csrf />
18 </http>
19
20 <!-- Select users and user_roles from database -->
21 <authentication-manager>
22 <authentication-provider>
23 <jdbc-user-service data-source-ref="dataSource"
24 users-by-username-query="select d_username username,d_password password, d_enabled enabled from t_users where d_username=?"
25 authorities-by-username-query="select d_username username, d_role role from t_user_roles where d_username=? " />
26 </authentication-provider>
27 </authentication-manager>
28
29 </beans:beans>
注意第9行,这里使用了一个el表达式,目的是/admin开头的url,必须有ADMIN角色的登录用户才可访问
第11行,表示如果登录用户权限不够,将跳转到/403这个url
24,25这二行,指定了查询用户/角色的sql语句,注意:虽然前面提到了用户/角色这二张表的表名/字段名可以随便写,但是写sql时,用户名的别名必须是username,密码列的别名必须是password,帐号有效状态的别名必须是enabled,而权限角色列的别名必须是role
23行指定了db数据源,它的详细定义在 spring-database.xml中,内容如下:
1 <?xml version="1.0" encoding="UTF-8"?>
2 <beans xmlns="http://www.springframework.org/schema/beans"
3 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
4 xsi:schemaLocation="http://www.springframework.org/schema/beans
5 http://www.springframework.org/schema/beans/spring-beans.xsd">
6
7 <bean id="dataSource"
8 class="org.springframework.jdbc.datasource.DriverManagerDataSource">
9 <property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
10 <property name="url" value="jdbc:oracle:thin:@172.21.***.***:1521:orcl" />
11 <property name="username" value="***" />
12 <property name="password" value="***" />
13 </bean>
14 </beans>
本文使用的是oracle数据库,如果是其它数据库,请自行调整上面的内容
四、Controller
1 package com.cnblogs.yjmyzz;
2
3 import org.springframework.security.authentication.AnonymousAuthenticationToken;
4 import org.springframework.security.core.Authentication;
5 import org.springframework.security.core.context.SecurityContextHolder;
6 import org.springframework.security.core.userdetails.UserDetails;
7 import org.springframework.stereotype.Controller;
8 import org.springframework.web.bind.annotation.RequestMapping;
9 import org.springframework.web.bind.annotation.RequestMethod;
10 import org.springframework.web.bind.annotation.RequestParam;
11 import org.springframework.web.servlet.ModelAndView;
12
13 @Controller
14 public class HelloController {
15
16 @RequestMapping(value = { "/", "/welcome" }, method = RequestMethod.GET)
17 public ModelAndView welcome() {
18
19 ModelAndView model = new ModelAndView();
20 model.addObject("title",
21 "Spring Security Login Form - Database Authentication");
22 model.addObject("message", "This is default page!");
23 model.setViewName("hello");
24 return model;
25
26 }
27
28 @RequestMapping(value = "/admin", method = RequestMethod.GET)
29 public ModelAndView admin() {
30
31 ModelAndView model = new ModelAndView();
32 model.addObject("title",
33 "Spring Security Login Form - Database Authentication");
34 model.addObject("message", "This page is for ROLE_ADMIN only!");
35 model.setViewName("admin");
36 return model;
37
38 }
39
40 @RequestMapping(value = "/login", method = RequestMethod.GET)
41 public ModelAndView login(
42 @RequestParam(value = "error", required = false) String error,
43 @RequestParam(value = "logout", required = false) String logout) {
44
45 ModelAndView model = new ModelAndView();
46 if (error != null) {
47 model.addObject("error", "Invalid username and password!");
48 }
49
50 if (logout != null) {
51 model.addObject("msg", "You've been logged out successfully.");
52 }
53 model.setViewName("login");
54
55 return model;
56
57 }
58
59 // for 403 access denied page
60 @RequestMapping(value = "/403", method = RequestMethod.GET)
61 public ModelAndView accesssDenied() {
62
63 ModelAndView model = new ModelAndView();
64
65 // check if user is login
66 Authentication auth = SecurityContextHolder.getContext()
67 .getAuthentication();
68 if (!(auth instanceof AnonymousAuthenticationToken)) {
69 UserDetails userDetail = (UserDetails) auth.getPrincipal();
70 model.addObject("username", userDetail.getUsername());
71 }
72
73 model.setViewName("comm/403");
74 return model;
75
76 }
77
78 }
66-71行演示了如何在服务端判断一个用户是否已经登录
五、视图页面
hello.jsp
1 <%@ page language="java" contentType="text/html; charset=UTF-8"
2 pageEncoding="UTF-8"%>
3 <%@taglib prefix="sec"
4 uri="http://www.springframework.org/security/tags"%>
5 <%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
6 <html>
7 <head>
8 <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
9 <title>${title}</title>
10 </head>
11 <body>
12 <h1>Title : ${title}</h1>
13 <h1>Message : ${message}</h1>
14 <sec:authorize access="hasRole('POWER')">
15 <!-- For login user -->
16 <c:url value="/j_spring_security_logout" var="logoutUrl" />
17 <form action="${logoutUrl}" method="post" id="logoutForm">
18 <input type="hidden" name="${_csrf.parameterName}"
19 value="${_csrf.token}" />
20 </form>
21 <script>
22 function formSubmit() {
23 document.getElementById("logoutForm").submit();
24 }
25 </script>
26
27 <c:if test="${pageContext.request.userPrincipal.name != null}">
28 <h2>
29 User : ${pageContext.request.userPrincipal.name} | <a
30 href="javascript:formSubmit()"> Logout</a> | <a href="admin">admin</a>
31 </h2>
32 </c:if>
33 </sec:authorize>
34
35 <sec:authorize access="isAnonymous()">
36 <br />
37 <h2>
38 <a href="login">login</a>
39 </h2>
40 </sec:authorize>
41
42 </body>
43 </html>
注意一下:14、27、35这三行,它们演示了如何在jsp端判断用户具有的角色权限、是否已登录等用法
403.jsp
1 <%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
2 <html>
3 <body>
4 <h1>HTTP Status 403 - Access is denied</h1>
5
6 <c:choose>
7 <c:when test="${empty username}">
8 <h2>You do not have permission to access this page!</h2>
9 </c:when>
10 <c:otherwise>
11 <h2>
12 Username : ${username} <br /> You do not have permission to access
13 this page!
14 </h2>
15 </c:otherwise>
16 </c:choose>
17
18 </body>
19 </html>
admin.jsp
1 <%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
2 <%@page session="true"%>
3 <html>
4 <body>
5 <h1>Title : ${title}</h1>
6 <h1>Message : ${message}</h1>
7
8 <c:url value="/j_spring_security_logout" var="logoutUrl" />
9 <form action="${logoutUrl}" method="post" id="logoutForm">
10 <input type="hidden" name="${_csrf.parameterName}"
11 value="${_csrf.token}" />
12 </form>
13 <script>
14 function formSubmit() {
15 document.getElementById("logoutForm").submit();
16 }
17 </script>
18
19 <c:if test="${pageContext.request.userPrincipal.name != null}">
20 <h2>
21 Welcome : ${pageContext.request.userPrincipal.name} | <a
22 href="javascript:formSubmit()"> Logout</a> | <a href="welcome">welcome</a>
23 </h2>
24 </c:if>
25
26 </body>
27 </html>
因为在xml中已经配置了/admin开头的请求url,必须具有ADMIN角色权限,所以admin.jsp端反而不用任何额外的判断了