The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note: 0 ≤ x, y < 2^31.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
题目可以理解为:求两个数有多少位是不一样的。那么步骤可以为:
public int hammingDistance(int x, int y) {
int val = x ^ y;
int result = 0;
while (val != 0) {
if ((val & 1) == 1) {
result++;
}
val >>= 1;
}
return result;
}