用不动点法和牛顿迭代法求解函数根-Julia

print("Input max iter times: ")
f=x->(x*x-3*x+2-exp(x))
g=x->(2*x-3-exp(x))
h=x->(x*x+2-exp(x))/3

n=parse(Int, readline())
t=n
x = -1
newton_x=-1
x1 = h(x)
newton_y=newton_x-f(newton_x)/g(newton_x)
println("不动点迭代法               牛顿迭代\n")
println("step$(0): $(x)                     step$(0):$(newton_y)")
while ((abs(x-x1)>=(1e-12))||(abs(newton_x-newton_y)>=(1e-12)))&&(n!=0)
	x = x1
    newton_x = newton_y
    println("step$(t-n): $(x1)     step$(t-n):$(newton_y)")
    x1 = h(x)
    newton_y=newton_x-f(newton_x)/g(newton_x)
	n-=1
end
println("step$(t-n): $(x1)     step$(t-n):$(newton_y)");