leetcode 9 Palindrome Number 回文数
leetcode 9 Palindrome Number 回文数
流川疯
发布于 2019-01-18 15:24:08
发布于 2019-01-18 15:24:08
Determine whether an integer is a palindrome. Do this without extra space.
click to show spoilers.
Some hints: Could negative integers be palindromes? (ie, -1)
If you are thinking of converting the integer to string, note the restriction of using extra space.
You could also try reversing an integer. However, if you have solved the problem “Reverse Integer”, you know that the reversed integer might overflow. How would you handle such case?
There is a more generic way of solving this problem.
非常简洁的c++解决方案： 对于回文数只比较一半
public boolean isPalindrome1(int x) {
if (x == 0) return true;
// in leetcode, negative numbers and numbers with ending zeros
// are not palindrome
if (x < 0 || x % 10 == 0)
return false;
// reverse half of the number
// the exit condition is y >= x
// so that overflow is avoided.
int y = 0;
while (y < x) {
y = y * 10 + (x % 10);
if (x == y) // to check numbers with odd digits
return true;
x /= 10;
}
return x == y; // to check numbers with even digits
}python这个解法应该是前后分别对比：
class Solution:
# @param x, an integer
# @return a boolean
def isPalindrome(self, x):
if x < 0:
return False
ranger = 1
while x / ranger >= 10:
ranger *= 10
while x:
left = x / ranger
right = x % 10
if left != right:
return False
x = (x % ranger) / 10
ranger /= 100
return Truepython字符串的解法：
class Solution:
# @param {integer} x
# @return {boolean}
def isPalindrome(self, x):
return str(x)==str(x)[::-1]本文参与 腾讯云自媒体分享计划，分享自作者个人站点/博客。
原始发表：2015年06月28日，如有侵权请联系 cloudcommunity@tencent.com 删除
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