shell脚本-三位随机数字 原

#!/bin/bash
##Random a nunber group
##Written by adai 2017-09-07
read -p "Please input a number:" a
if [ $a -lt 3 ]
then
    for i in `seq 1 3`
    do
        m=`echo $RANDOM`
        n=$[ $m % 10 ]
        echo "$n" >> /tmp/count.txt
        a=$a+1
    done
    cat /tmp/count.txt |xargs -n3
    >/tmp/count.txt
elif [ $a -ge 3 ]
    b=`expr $a \* 3`
then
    for i in `seq 1 $b`
    do
        m=`echo $RANDOM`
        n=$[ $m % 10 ]
        echo "$n" >> /tmp/count.txt
    done
fi

#!/bin/bash
get_a_num() {
    n=$[$RANDOM%10]
    echo $n
}

get_numbers() {
    for i in 1 2 3; do
        a[$i]=`get_a_num`
    done
    echo ${a[@]}
}

if [ -n "$1" ]; then
    m=`echo $1|sed 's/[0-9]//g'`
    if [ -n "$m" ]; then
        echo "Useage bash $0 n, n is a number, example: bash $0 5"
        exit
    else
        for i in `seq 1 $1`
        do
            get_numbers
        done
    fi
else
    get_numbers
fi