检测地址能否打开[python] 原

3.6.2

import urllib.request   import time   opener = urllib.request.build_opener()   opener.addheaders = [('User-agent', 'Mozilla/49.0.2')]   #这个是你放网址的文件名，改过来就可以了   # file = open('test.txt')   # lines = file.readlines()   aa=['http://www.baidu.com/','http://www.baidu.com']   # for line in lines:   #     temp=line.replace('\n','')   #     aa.append(temp)   # print(aa)   print('开始检查：')   for a in aa:       tempUrl = a       try :           opener.open(tempUrl)           print(tempUrl+'没问题')       except urllib.error.HTTPError:           print(tempUrl+'=访问页面出错')           time.sleep(2)       except urllib.error.URLError:           print(tempUrl+'=访问页面出错')           time.sleep(2)       time.sleep(0.1)  

2.6

#!/usr/bin/python2.6   # -*- coding: utf-8 -*-   import urllib2 import time

opener = urllib2.build_opener() opener.addheaders = [('User-agent', 'Mozilla/49.0.2')] #这个是你放网址的文件名，改过来就可以了   # file = open('test.txt')   # lines = file.readlines()   aa=['http://www.baidu.com.com/','http://www.baidu.com']   # for line in lines:   #     temp=line.replace('\n','')   #     aa.append(temp)   # print(aa)  

print('开始检查：') for a in aa:     tempUrl = a     try :         opener.open(tempUrl)         print(tempUrl+'没问题')     except urllib.error.HTTPError:         print(tempUrl+'=访问页面出错')         time.sleep(2)     except urllib.error.URLError:         print(tempUrl+'=访问页面出错')         time.sleep(2)     time.sleep(0.1)

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