分析:注意本题要求的是没有动拆的烟囱数量,不包含没拆完的。
#include <iostream>#include <cmath>using namespace std;int main(){ int n, day, y; cin >> n >> day >> y; cout << ceil((day * 24 * 1.0) / y) << endl; return 0;}
#include <iostream>using namespace std;int main(){ int n, m; cin >> n >> m; int cnt = n; for(int i = 0; i < n; i++) { int k; cin >> k; if(0 == k % m) { while(k) { if(k % 10 == m) { cnt++; break; } k /= 10; } } } cout << cnt << endl; return 0;}
#include<iostream>using namespace std;bool isprime(int n){ for(int i = 2; i * i <= n; i++) { if(n % i == 0) { return false; } } return true;}int gcd(int a, int b){ return b == 0 ? a : gcd(b, a % b);}int main() { int m, n; cin >> n >> m; int q = gcd(n, m); for(int res = q; res >= 2; res--) { if(isprime(res)) { cout << res << endl; return 0; } } cout << 0 << endl; return 0; }