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社区首页 >专栏 >Leetcode 138. Copy List with Random Pointer

Leetcode 138. Copy List with Random Pointer

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Tyan
发布2019-05-25 22:18:49
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发布2019-05-25 22:18:49
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文章被收录于专栏:SnailTyanSnailTyan

版权声明:博客文章都是作者辛苦整理的,转载请注明出处,谢谢! https://cloud.tencent.com/developer/article/1433644

文章作者:Tyan

博客:noahsnail.com | CSDN | 简书

1. Description

2. Solution

  • Version 1
代码语言:javascript
复制
/**
 * Definition for singly-linked list with a random pointer.
 * struct RandomListNode {
 *     int label;
 *     RandomListNode *next, *random;
 *     RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
 * };
 */
class Solution {
public:
    RandomListNode *copyRandomList(RandomListNode *head) {
        if(!head) {
            return nullptr;
        }
        vector<RandomListNode*> origin;
        vector<RandomListNode*> target;
        RandomListNode* result = new RandomListNode(head->label);
        origin.push_back(head);
        target.push_back(result);
        RandomListNode* prev = result;
        RandomListNode* current = head->next;
        while(current) {
            RandomListNode* node = new RandomListNode(current->label);
            prev->next = node;
            prev = node;
            origin.push_back(current);
            target.push_back(node);
            current = current->next;
        }
        for(int i = 0; i < origin.size(); i++) {
            if(!origin[i]->random) {
                continue;
            }
            for(int j = 0; j < origin.size(); j++) {
                if(origin[i]->random == origin[j]) {
                    target[i]->random = target[j];
                    break;
                }
            }
        }
        return result;
    }
};
  • Version 2
代码语言:javascript
复制
/**
 * Definition for singly-linked list with a random pointer.
 * struct RandomListNode {
 *     int label;
 *     RandomListNode *next, *random;
 *     RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
 * };
 */
class Solution {
public:
    RandomListNode *copyRandomList(RandomListNode *head) {
        if(!head) {
            return nullptr;
        }
        unordered_map<RandomListNode*, RandomListNode*> correspond;
        RandomListNode* result = new RandomListNode(head->label);
        RandomListNode* prev = result;
        RandomListNode* current = head->next;
        correspond[head] = result;
        while(current) {
            RandomListNode* node = new RandomListNode(current->label);
            prev->next = node;
            prev = node;
            correspond[current] = node;
            current = current->next;
        }
        RandomListNode* copy_current = result;
        current = head;
        while(current) {
            copy_current->random = correspond[current->random];
            current = current->next;
            copy_current = copy_current->next;
        }
        return result;
    }
};
  • Version 3
代码语言:javascript
复制
/**
 * Definition for singly-linked list with a random pointer.
 * struct RandomListNode {
 *     int label;
 *     RandomListNode *next, *random;
 *     RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
 * };
 */
class Solution {
public:
    RandomListNode *copyRandomList(RandomListNode *head) {
        if(!head) {
            return nullptr;
        }
        RandomListNode* current = head;
        while(current) {
            RandomListNode* node = new RandomListNode(current->label);
            node->next = current->next;
            current->next = node;
            current = current->next->next;
        }
        current = head;
        while(current) {
            if(current->random) {
                current->next->random = current->random->next;
            }
            current = current->next->next;
        }
        RandomListNode* result = head->next;
        RandomListNode* copy_current = head->next;
        current = head;
        while(current) {
            current->next = current->next->next;
            if(copy_current->next) {
                copy_current->next = copy_current->next->next;
            }
            else {
                copy_current->next = nullptr;
            }
            current = current->next;
            copy_current = copy_current->next;
        }
        return result;
    }
};

Reference

  1. https://leetcode.com/problems/copy-list-with-random-pointer/description/
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原始发表:2018年09月03日,如有侵权请联系 cloudcommunity@tencent.com 删除

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  • 1. Description
  • 2. Solution
  • Reference
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