LintCode-8.旋转字符串

offset=0 => "abcdefg"
offset=1 => "gabcdef"
offset=2 => "fgabcde"
offset=3 => "efgabcd"

public class Solution {
    /**
     * @param str: an array of char
     * @param offset: an integer
     * @return: nothing
     */
    public void rotateString(char[] str, int offset) {
        // write your code here
        char temp;
        if(str.length == 0) return;
        if(offset == 0) return;
        if(str.length < offset) offset = offset % str.length;
        while(offset>0){
            temp = str[str.length-1];
            for(int i = str.length - 1; i > 0;i--){
                str[i] = str[i-1];
            }
            str[0]=temp;
            offset--;
        }
    }
}