LeetCode-2. Add Two Numbers

悠扬前奏

发布于 2019-06-02 12:58:38

2270

发布于 2019-06-02 12:58:38

Problem

Description

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

Answer

Thinking

Nothing

Code

/**
 * Definition for singly-linked list.
 * function ListNode(val) {
 *     this.val = val;
 *     this.next = null;
 * }
 */
/**
 * @param {ListNode} l1
 * @param {ListNode} l2
 * @return {ListNode}
 */
var addTwoNumbers = function(l1, l2) {
    var carry = 0;
    var sum = l1.val + l2.val,n1 = l1.next,n2 = l2.next;
    var head = new ListNode(sum % 10), temp = head;
    sum = Math.floor(sum / 10);
    while(n1 || n2 || sum !== 0){
        sum += (n1?n1.val:0)+(n2?n2.val:0);
        temp.next = new ListNode(sum%10);
        temp = temp.next;
        n1 = n1 ? n1.next : null;
        n2 = n2 ? n2.next : null;
        sum = Math.floor(sum / 10);
    }
    return head;
};

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原始发表：2017.06.20 ，如有侵权请联系 cloudcommunity@tencent.com 删除

digits