原问题是将左边样式变成右边样式:
即有父类和子类,父类包括多个子类,怎样将子类匹配到父类下面的问题
代码如下
1 #!/usr/bin/python3.4
2 # -*- coding: utf-8 -*-
3
4 arr1 = ["S01","S01","S01","S02","S03","S04","S04"]
5 arr2 = ["G0001","G0002","G0003","G0004","G0003","G0004","G0005"]
6 # 用来存放父类
7 father = []
8 # 放入第一个单方便后面循环计算
9 father.append(arr1[0])
10 # 子类
11 son = []
12 # 临时数组
13 temp = []
14
15 for i in range(0,len(arr1)):
16 # 如果father里面存在,就跳过
17 # 把子类存入临时数组
18 if arr1[i] in father:
19 temp.append(arr2[i])
20 pass
21 # 如果father里面不存在
22 # 释放临时数组
23 else:
24 son.append(temp)
25 temp = []
26 father.append(arr1[i])
27 temp.append(arr2[i])
28 # 将最后一次循环的temp放入son
29 son.append(temp)
30 print(father)
31 print(son)
运行效果: