python笔记39-unittest框架如何将上个接口的返回结果给下个接口适用(面试必问)

print(globals())# 用法
globals()["a"] = "用例a的返回结果"# 用例b引用
b = globals()["a"]
print(b)

import unittest
import requestsclass TestA(unittest.TestCase):
def setUp(self):
self.s = requests.session()def test_a(self):
'''用例a'''
result_a = "aaaaaa"    # 用例a的返回值# 返回值先给全部办理，存到字典对应key
globals()["a"] = result_a
self.assertEqual(result_a, "aaaaaa")def test_b(self):
'''用例b'''
b = globals()["a"]  # 引用用例a的返回值
print("用例b引用用例a的返回值：%s"%b)
result_b = b+"111"
self.assertEqual(result_b, "aaaaaa111")if __name__ == '__main__':
unittest.main()

E:\python36\python.exe D:/jiekou9/debug/yilai.py
..
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Ran 2 tests in 0.000sOK
用例b引用用例a的返回值：aaaaaa

import unittest
import requestsclass TestA(unittest.TestCase):
'''上海悠悠：QQ群：779429633'''
def setUp(self):
self.s = requests.session()
self.g = globals()def test_a(self):
'''用例a'''
result_a = "aaaaaa"    # 用例a的返回值# 返回值先给全部办理，存到字典对应key
self.g["a"] = result_a
self.assertEqual(result_a, "aaaaaa")def test_b(self):
'''用例b'''
b = self.g["a"]  # 引用用例a的返回值
print("用例b引用用例a的返回值：%s"%b)
result_b = b+"111"
self.g["b"] = result_b
self.assertEqual(result_b, "aaaaaa111")def test_c(self):
'''用例c'''
print("用例c依赖用例a和用例b")c_a = self.g["a"]
c_b = self.g["b"]
print("用例c的请求入参：%s" % c_a)
print("用例c的请求入参：%s" % c_b)if __name__ == '__main__':
unittest.main()

.用例b引用用例a的返回值：aaaaaa
.用例c依赖用例a和用例b
用例c的请求入参：aaaaaa
用例c的请求入参：aaaaaa111
.
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Ran 3 tests in 5.001sOK