1.将一个给定的整型数组转置输出, 例如: 源数组,1 2 3 4 5 6 转置之后的数组,6 5 4 3 2 1
package Array;
public class arrayTest1 {
public static void main(String[] args) {
int[] a={1,2,3,4,5,6};
int m=a.length;
int temp;
for (int i = 0; i <m/2; i++) {
temp=a[i];
a[i]=a[m-i-1];
a[m-i-1]=temp;
}
for (int i = 0; i < m; i++) {
System.out.print(a[i]+" ");
}
}
}
2.现在有如下的一个数组: int[] oldArr = {1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} ; 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为: int[] newArr = {1,3,4,5,6,6,5,4,7,6,7,5} ;
package Array;
public class arrayTest2 {
public static void main(String[] args) {
int[] oldArr = {1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} ;
int count=0;
for (int i = 0; i <oldArr.length ; i++) {
if(oldArr[i]!=0){
count++;
}
}
int[] newArr=new int[count];
for (int i = 0,j=0; i <oldArr.length ; i++) {
if(oldArr[i]!=0)
{
newArr[j]=oldArr[i];
j++;
}
}
System.out.print("新数组为:");
for (int i = 0; i < count; i++) {
System.out.print(newArr[i]+" ");
}
}
}
3.现在给出两个数组: 数组a:"1,7,9,11,13,15,17,19" 数组b:"2,4,6,8,10" 两个数组合并为数组c。
package Array;
import java.util.ArrayList;
import java.util.List;
public class arrayTest3 {
public static void main(String[] args) {
int[] a = {1, 7, 9, 11, 13, 15, 17, 19};
int[] b = {2, 4, 6, 8, 10};
int m = a.length + b.length;
int j = 0,temp;
int[] c = new int[m];
for (int i = 0; i < a.length; i++) {
c[i] = a[i];
}
for (int i = a.length; i < m; i++) {
c[i] = b[j];
j++;
}
for(int i=0;i<m-1;i++){
for(int s=0;s<m-1-i;s++){
if(c[s]>c[s+1]){
temp=c[s];
c[s]=c[s+1];
c[s+1]=temp;
}
}
}
for (int i = 0; i < m; i++) {
System.out.print(c[i] + " ");
}
}
}