【leetcode系列】169. 求众数

给定一个大小为 n 的数组，找到其中的众数。众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素。

你可以假设数组是非空的，并且给定的数组总是存在众数。

示例 1:

输入: [3,2,3]
输出: 3
示例 2:

输入: [2,2,1,1,1,2,2]
输出: 2

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/majority-element
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/*
 * @lc app=leetcode id=169 lang=javascript
 *
 * [169] Majority Element
 *
 * https://leetcode.com/problems/majority-element/description/
 *
 * algorithms
 * Easy (51.62%)
 * Total Accepted:    365.6K
 * Total Submissions: 702.5K
 * Testcase Example:  '[3,2,3]'
 *
 * Given an array of size n, find the majority element. The majority element is
 * the element that appears more than ⌊ n/2 ⌋ times.
 *
 * You may assume that the array is non-empty and the majority element always
 * exist in the array.
 *
 * Example 1:
 *
 *
 * Input: [3,2,3]
 * Output: 3
 *
 * Example 2:
 *
 *
 * Input: [2,2,1,1,1,2,2]
 * Output: 2
 *
 *
 */
/**
 * @param {number[]} nums
 * @return {number}
 */
var majorityElement = function(nums) {
    let count = 1;
    let majority = nums[0];
    for(let i = 1; i < nums.length; i++) {
        if (count === 0) {
            majority = nums[i];
        }
        if (nums[i] === majority) {
            count ++;
        } else {
            count --;
        }
    }
    return majority;
};