给一颗树,每条边有一个权值。有两种操作:1、修改某条边的值;2、询问a、b两点路径上边权的最大值。
#include <iostream>
#include <bits/stdc++.h>
using namespace std;
#define pii pair<int,int>
#define ll long long
#define mst(a,b) memset(a,b,sizeof(a))
#define rep(i,a,b) for(ll i=(a);i<(b);++i)
#define rrep(i,a,b) for(ll i=(b-1);i>=a;--i)
#define fi first
#define se second
#define sz size()
#define lb lower_bound
#define ub upper_bound
#define pb push_back
const double eps = 1e-8, PI = acos(-1.0f);
const int inf = 0x3f3f3f3f, maxN = 1e4 + 5;
int N, M, T;
// 线段树
#define lson l, m, rt << 1
#define rson m + 1, r, rt << 1 | 1
int seg[maxN << 2];
void push_up(int rt) { seg[rt] = max(seg[rt << 1], seg[rt << 1 | 1]); }
void build(int l, int r, int rt) {
seg[rt] = 0;
if (l == r) return;
int m = (l + r) >> 1;
build(lson);
build(rson);
}
int query(int L, int R, int l, int r, int rt) {
if (L <= l && r <= R)
return seg[rt];
int m = (l + r) >> 1;
int ret = 0;
if (L <= m) ret = max(ret, query(L, R, lson));
if (R > m) ret = max(ret, query(L, R, rson));
return ret;
}
void update(int p, int x, int l, int r, int rt) {
if (l == r) {
seg[rt] = x;
return;
}
int m = (r + l) >> 1;
if (p <= m) update(p, x, lson);
else update(p, x, rson);
push_up(rt);
}
// 树链剖分
struct Edge {
int to, next;
} edge[maxN * 2];
int head[maxN], tot;
int top[maxN]; // top[v]即v所在重链的顶端结点
int fa[maxN]; // 父节点
int deep[maxN]; // 深度
int num[maxN]; // num[v] 以v为根的子树结点数
int p[maxN]; // p[v]为v的dfs位置
int fp[maxN]; // 与p相反
int son[maxN]; // 重子编号
int pos;
void init() {
tot = 0;
pos = 0;
mst(head, -1);
mst(son, -1);
}
void addEdge(int u, int v) {
edge[tot].to = v;
edge[tot].next = head[u];
head[u] = tot++;
}
void dfs1(int u, int pre, int d) {
deep[u] = d;
fa[u] = pre;
num[u] = 1;
for (int i = head[u]; i != -1; i = edge[i].next) {
int v = edge[i].to;
if (v != pre) {
dfs1(v, u, d + 1);
num[u] += num[v];
if (son[u] == -1 || num[v] > num[son[u]])
son[u] = v;
}
}
}
void getPos(int u, int sp) {
top[u] = sp;
p[u] = pos++;
fp[p[u]] = u;
if (son[u] == -1)
return;
getPos(son[u], sp);
for (int i = head[u]; i != -1; i = edge[i].next) {
int v = edge[i].to;
if (v != son[u] && v != fa[u])
getPos(v, v);
}
}
// 查询u->v边的max
int findMax(int u, int v) {
int f1 = top[u], f2 = top[v];
int tmp = 0;
while (f1 != f2) {
if (deep[f1] < deep[f2]) {
swap(f1, f2);
swap(u, v);
}
tmp = max(tmp, query(p[f1], p[u], 0, pos - 1, 1));
u = fa[f1];
f1 = top[u];
}
if (u == v) return tmp;
if (deep[u] > deep[v]) swap(u, v);
return max(tmp, query(p[son[u]], p[v], 0, pos - 1, 1));
}
int e[maxN][3];
// CHANGE i ti 修改第i条边的值为ti
// QUERY a b 询问a到b的最大边权
// DONE 结束符号
int main() {
//#ifndef ONLINE_JUDGE
// freopen("data.in", "r", stdin);
//#endif
scanf("%d", &T);
while (T--) {
init();
scanf("%d", &N);
rep(i, 0, N - 1) {
scanf("%d%d%d", &e[i][0], &e[i][1], &e[i][2]);
addEdge(e[i][0], e[i][1]);
addEdge(e[i][1], e[i][0]);
}
dfs1(1, 0, 0);
getPos(1, 1);
build(0, pos - 1, 1);
rep(i, 0, N - 1) {
if (deep[e[i][0]] > deep[e[i][1]])
swap(e[i][0], e[i][1]);
update(p[e[i][1]], e[i][2], 0, pos - 1, 1);
}
char op[10];
int u, v;
while (~scanf("%s", op)) {
if (op[0] == 'D') break;
scanf("%d %d", &u, &v);
if (op[0] == 'C')
update(p[e[u - 1][1]], v, 0, pos - 1, 1);
else
printf("%d\n", findMax(u, v));
}
}
return 0;
}