1014 福尔摩斯的约会 (20 分)
代码
// 1014 福尔摩斯的约会 (20 分).cpp : 此文件包含 "main" 函数。程序执行将在此处开始并结束。
//
#include <iostream>
#include <string>
#include <vector>
using namespace std;
int find_same(string str1, string str2, int index, int number) {
//两串字符串找出第一个相同的位置
int size = str1.size();
if (size > str2.size())
size = str2.size();
for (; index < size; index++) {
if (number == 1 && str1[index] == str2[index] && str1[index] >= 'A' && str1[index] <= 'G')
return index;
if (number == 2 && str1[index] == str2[index] && ((str1[index] >= 'A' && str1[index] <= 'N') || (str1[index] >= '0' && str1[index] <= '9')))
return index;
if (number == 3 && str1[index] == str2[index] && isalpha(str1[index]))
return index;
}
return 0;
}
int main(){
string input;
vector<string> input_vector;
//输入4串
int num = 4;
while (num) {
cin >> input;
input_vector.push_back(input);
num--;
}
//Day:某星期
int Day_number = find_same(input_vector[0], input_vector[1], 0, 1);
char Day = input_vector[0][Day_number];
//Hour:某个小时
int Hour_number = find_same(input_vector[0], input_vector[1], Day_number + 1, 2);
char Hour = input_vector[0][Hour_number];
//Min:分钟
int Min = find_same(input_vector[2], input_vector[3], 0, 3);
//输出日期
switch (Day){
case 'A' :
cout << "MON ";
break;
case 'B':
cout << "TUE ";
break;
case 'C':
cout << "WED ";
break;
case 'D':
cout << "THU ";
break;
case 'E':
cout << "FRI ";
break;
case 'F':
cout << "SAT ";
break;
case 'G':
cout << "SUN ";
break;
}
if (Hour >= '0' && Hour <= '9')
cout << "0" << Hour << ":";
if (Hour >= 'A' && Hour <= 'N') {
int temp = Hour - 'A' + 10;
cout << temp << ":";
}
if (Min >= 0 && Min <= 9) {
cout << "0" << Min;
}
if (Min >= 10 && Min <= 60) {
cout << Min;
}
}
这题目只要搞清楚了约束条件就很简单了,不细说。