每天一道leetcode443-压缩字符串

class Solution {
    public int compress(char[] chars) {
        int count = 1; 
        int index = 0;
        for (int i = 0; i < chars.length; i++) {
            if (i + 1 == chars.length || chars[i] != chars[i+1]) {
                chars[index++] = chars[i];
                if (count > 1) {
                    String temp = String.valueOf(count);
                    for(int k=0;k<temp.length();k++)
                        chars[index++] = temp.charAt(k);
                }
                count = 1;
            }
            else {
                count++;//统计重复字符的个数
            }
        }
        return index;
    }
}