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题目部分
在Oracle中,降序索引和升序索引分别是什么?
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答案部分
对于升序索引(Ascending Indexes),数据库按升序排列的顺序存储数据。索引默认按照升序存储列值。默认情况下,字符数据按每个字节中包含的二进制值排序,数值数据按从小到大排序,日期数据从早到晚排序。
降序索引(Descending Indexes)将存储在一个特定的列或多列中的数据按降序排序。创建降序索引时使用DESC关键字,如下所示:
CREATE INDEX IND_DESC ON TESTDESC(A DESC,B ASC);
需要注意的是,降序索引在DBA_INDEXES的INDEX_TYPE列表现为FUNCTION-BASED即函数索引,但是在DBA_IND_EXPRESSIONS不能体现其升序或降序,只能通过视图DBA_IND_COLUMNS的DESCEND列来查询,如下所示:
先创建表和索引:
CREATE TABLE XT_DESC_LHR AS SELECT * FROM DBA_OBJECTS;
CREATE INDEX IND_DESC_LHR ON XT_DESC_LHR(OBJECT_ID DESC,OBJECT_NAME ASC);
CREATE INDEX IND_DESC_LHR2 ON XT_DESC_LHR(OBJECT_NAME DESC);
CREATE INDEX IND_DESC_LHR3 ON XT_DESC_LHR(OBJECT_type ASC);
查询索引:
SYS@orclasm > SELECT D.INDEX_NAME,D.INDEX_TYPE FROM DBA_INDEXES D WHERE D.INDEX_NAME LIKE 'IND_DESC_LHR%';
INDEX_NAME INDEX_TYPE
------------------------------ ---------------------------
IND_DESC_LHR FUNCTION-BASED NORMAL
IND_DESC_LHR2 FUNCTION-BASED NORMAL
IND_DESC_LHR3 NORMAL
SYS@orclasm > SET LINE 9999
SYS@orclasm > SELECT D.INDEX_NAME,D.COLUMN_EXPRESSION FROM DBA_IND_EXPRESSIONS D WHERE D.INDEX_NAME LIKE 'IND_DESC_LHR%' ;
INDEX_NAME COLUMN_EXPRESSION
------------------------------ -------------------------
IND_DESC_LHR "OBJECT_ID"
IND_DESC_LHR2 "OBJECT_NAME"
SYS@orclasm > COL COLUMN_NAME FORMAT A15
SYS@orclasm > SELECT d.INDEX_NAME,d.COLUMN_NAME,d.COLUMN_POSITION,d.DESCEND FROM DBA_IND_COLUMNS D WHERE D.INDEX_NAME LIKE 'IND_DESC_LHR%' ORDER BY d.INDEX_NAME,d.COLUMN_POSITION;
INDEX_NAME COLUMN_NAME COLUMN_POSITION DESC
------------------------------ --------------- --------------- ----
IND_DESC_LHR SYS_NC00016$ 1 DESC
IND_DESC_LHR OBJECT_NAME 2 ASC
IND_DESC_LHR2 SYS_NC00017$ 1 DESC
IND_DESC_LHR3 OBJECT_TYPE 1 ASC
SYS@orclasm > SELECT COLUMN_NAME,DATA_TYPE,DATA_DEFAULT FROM DBA_TAB_COLS WHERE OWNER='LHR' AND TABLE_NAME='XT_DESC_LHR' AND COLUMN_NAME='SYS_NC00016$';
COLUMN_NAME DATA_TYPE DATA_DEFAULT
------------------------------ ---------------------- -----------------
SYS_NC00016$ RAW "OBJECT_ID"
LHR@orclasm > SELECT * FROM XT_DESC_LHR t WHERE t.object_name='LHR' AND T.OBJECT_ID=1 ORDER BY OBJECT_ID DESC,OBJECT_NAME ASC;
no rows selected
Execution Plan
----------------------------------------------------------
Plan hash value: 902722624
--------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
--------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 8 | 1656 | 2 (0)| 00:00:01 |
| 1 | TABLE ACCESS BY INDEX ROWID| XT_DESC_LHR | 8 | 1656 | 2 (0)| 00:00:01 |
|* 2 | INDEX RANGE SCAN | IND_DESC_LHR | 1 | | 1 (0)| 00:00:01 |
--------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
2 - access(SYS_OP_DESCEND("OBJECT_ID")=HEXTORAW('3EFDFF') AND
"T"."OBJECT_NAME"='LHR')
filter(SYS_OP_UNDESCEND(SYS_OP_DESCEND("OBJECT_ID"))=1)
Note
-----
- dynamic sampling used for this statement (level=2)
Statistics
----------------------------------------------------------
0 recursive calls
0 db block gets
2 consistent gets
0 physical reads
0 redo size
1343 bytes sent via SQL*Net to client
508 bytes received via SQL*Net from client
1 SQL*Net roundtrips to/from client
0 sorts (memory)
0 sorts (disk)
0 rows processed
本文选自《Oracle程序员面试笔试宝典》,作者:李华荣。