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数据库表关系如下
数据库sql执行如下:
mapper 中 resultMap标签配置如下:
<!-- 定义User的resultMap-->
<resultMap id="userAccountMap" type="user">
<id property="id" column="id"></id>
<result property="username" column="username"></result>
<result property="address" column="address"></result>
<result property="sex" column="sex"></result>
<result property="birthday" column="birthday"></result>
<!-- 配置user对象中accounts集合的映射 -->
<collection property="accounts" ofType="account">
<id column="aid" property="id"></id>
<result column="uid" property="uid"></result>
<result column="money" property="money"></result>
</collection>
</resultMap>
<!-- 查询所有 -->
<select id="findAll" resultMap="userAccountMap">
select * from user u left outer join account a on u.id = a.uid
</select>
业务mode Use类
public class User implements Serializable {
private Integer id;
private String username;
private String address;
private String sex;
private Date birthday;
}
//一对多关系映射:主表实体应该包含从表实体的集合引用
private List<Account> accounts;
account类如下
public class Account implements Serializable {
private Integer id;
private Integer uid;
private Double money;
}
test
/**
* 测试查询所有
*/
@Test
public void testFindAll(){
List<User> users = userDao.findAll();
for(User user : users){
System.out.println("-----每个用户的信息------");
System.out.println(user);
System.out.println(user.getAccounts());
}
}
输出结果
SQL语句: SELECT u.*,a.id AS aid,a.uid,a.money FROM account a , USER u WHERE u.id = a.uid;
mapper配置
<!-- 定义封装account和user的resultMap -->
<resultMap id="accountUserMap" type="account">
<id property="id" column="aid"></id>
<result property="uid" column="uid"></result>
<result property="money" column="money"></result>
<!-- 一对一的关系映射:配置封装user的内容
collection 集合 代表一对多-->
<association property="user" column="uid" javaType="user">
<id property="id" column="id"></id>
<result column="username" property="username"></result>
<result column="address" property="address"></result>
<result column="sex" property="sex"></result>
<result column="birthday" property="birthday"></result>
</association>
</resultMap>
<!-- 查询所有 -->
<select id="findAll" resultMap="accountUserMap">
select u.*,a.id as aid,a.uid,a.money from account a , user u where u.id = a.uid;
</select>
Test
/**
* 测试查询所有
*/
@Test
public void testFindAll(){
List<Account> accounts = accountDao.findAll();
for(Account account : accounts){
System.out.println("--------每个account的信息------------");
System.out.println(account);
System.out.println(account.getUser());
}
输出结果
SQL语句: select u.*,r.id as rid,r.role_name,r.role_desc from role r left outer join user_role ur on r.id = ur.rid left outer join user u on u.id = ur.uid
mapper配置
<!--定义role表的ResultMap-->
<resultMap id="roleMap" type="role">
<id property="roleId" column="rid"></id>
<result property="roleName" column="role_name"></result>
<result property="roleDesc" column="role_desc"></result>
<collection property="users" ofType="user">
<id column="id" property="id"></id>
<result column="username" property="username"></result>
<result column="address" property="address"></result>
<result column="sex" property="sex"></result>
<result column="birthday" property="birthday"></result>
</collection>
</resultMap>
业务mode Role类
public class Role implements Serializable {
private Integer roleId;
private String roleName;
private String roleDesc;
//多对多的关系映射:一个角色可以赋予多个用户
private List<User> users;
}
Test
/**
* 测试查询所有
*/
@Test
public void testFindAll(){
List<Role> roles = roleDao.findAll();
for(Role role : roles){
System.out.println("---每个角色的信息----");
System.out.println(role);
System.out.println(role.getUsers());
}
}
输出结果