list等分，两种实现方法

from math import ceil

def divide(lst, size):
    if size <= 0:
        return [lst]
    return [lst[i * size:(i+1)*size] for i in range(0, ceil(len(lst) / size))]

divide([1, 3, 5, 7, 9], 0)# [[1, 3, 5, 7, 9]]
divide([1, 3, 5, 7, 9], 2)# [[1, 3], [5, 7], [9]]

from math import ceil


def divide_iter(lst, n):
    if n <= 0:
        yield lst
        return
    i, div = 0, ceil(len(lst) / n)
    while i < n:
        yield lst[i * div: (i + 1) * div]
        i += 1


list(divide_iter([1, 2, 3, 4, 5], 0))  # [[1, 2, 3, 4, 5]]
list(divide_iter([1, 2, 3, 4, 5], 2))  # [[1, 2, 3], [4, 5]]