Python3下的【并行迭代】与【按索引

# Demo：并行迭代 zip函数names = ["anne","beth","george","damon","bob"]ages = [12,45,32,102,101,103]# names 与 ages 列表元素可以不等同，按数量少的进行对应for name,age in zip(names,ages):     print(name,"is",age,"years old!")按索引迭代案例按索引迭代方式一strings = ["Alice","Bob","Nick"]# strings[1] = "leo" #测试给列表添加元素后，的效果# print(strings)index = 0for string in strings:    if "ob" in string:        strings[index] = "Tom" # 将含有“ob”的元素，替换为Tom    index += 1print(strings)按索引迭代方式二strings = ["Alice","Bob","Nick"]index = 0for index,string in enumerate(strings):     if "ob" in string:        strings[index] = "Tom"print(strings)