python3 三级菜单-基础版

py3study

发布于 2020-01-03 11:03:26

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发布于 2020-01-03 11:03:26

文章被收录于专栏：python3

-- coding:utf-8 --

data = { "北京":{ "东城区":{ "安定门":["国子监","孔庙","钟楼"], "建国门":["金宝街","长安街","西街"], "朝阳门":["东四","新街口","孚王府"], }, "朝阳区":{ "和平街":["顾家庄","樱花社区","东街"], "八里屯":["慈寿寺","定慧寺","前门"], "三里屯":["夜店","工体","后海酒吧"], }, "海淀":{ "中关村":["海龙","鼎好","科贸"], "五道口":["清华","北大","人大"], "航天桥":["公主坟","古城","长安街"], }, } }

exit_flag =False

while not exit_flag: for i in data: print(i)

choice = input("选择1")
if choice in data:
    while not exit_flag:
        for i2 in  data[choice]:
            print("\t",i2)
        choice2 = input("选择2")
        if choice2 in data[choice]:
            while not exit_flag:
                for i3 in data[choice][choice2]:
                    print("\t\t",i3)
                choice3 = input("选择3")
                if choice3 in data[choice][choice2]:
                    for i4 in data[choice][choice2][choice3]:
                        print("\t\t\t",i4)
                    choice4 = input("最后一层，按b返回")
                    if choice4 == "b":
                        pass
                    elif choice4 == "q":
                        exit_flag = True
                if choice3 == "b":
                    break
                elif choice3 == "q":
                    exit_flag = True
        if choice2 == "b":
            break
        elif choice2 == "q":
            exit_flag = True

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原始发表：2019/09/26 ，如有侵权请联系 cloudcommunity@tencent.com 删除

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