Python11 集合

list_1 = [1,2,3,4,2,4,7,8,9]        #列表中有重复的内容

list_1 = set(list_1)            #将列表转成集合

print (list_1,type(list_1))

list_2 = set([7,8,9,11,12,13])

print (list_1.intersection(list_2))

print (list_1.union(list_2))

print (list_1.difference(list_2))

print (list_2.difference(list_1))

print (list_1.symmetric_difference(list_2))

 list_3 = set([1,3,7])

print (list_3.issubset(list_1))        

#判断list_3是否是list_1的子集（list_3的1,3,7在list_1中也存在）

print (list_1.issuperset(list_3))    #判断list_1是list_3的父集

print (list_3.issuperset(list_1))    #判断list_3是list_1的父集

list_4 = set([5,6,8])

print (list_3.isdisjoint(list_4))

list_1 = set([1,2,3,4,2,4,7,8,9])

list_2 = set([7,8,9,11,12,13])

list_3 = set([1,3,7])

list_4 = set([5,6,8])

print (list_1 & list_2)               #交集
print (list_1 | list_2)                 #并集
print (list_1 - list_2)             #差集，我有你没有
print (list_1 ^ list_2)            #对称差集

list_1.add(999)
print (list_1)

list_1.update([666,777,888])
print (list_1)

list_1.remove(999)
print (list_1)

print (list_1.remove('bbb'))    #删除

list_1.discard(666)
print (list_1)