解释*args和**kwargs的含义

def func(*args):
    for i in args:
        print(i)
func(3,2,1,4,7)

Output:
-----
3
2
1
4
7
-----

def func(**kwargs):
    for i in kwargs:
        print(i,kwargs[i])
func(a=1,b=2,c=7)

Output:
------
a 1
c 7
b 2
------