Python_编程题集_001_词法解析

import string #引用string模块完成解析
def find(s):
    digit = []  #存储数字
    letter = [] #存储字母、拼音
    punctuation = [] #存储符号、空格   
    chinese = []    #存储中文
    for i in s:
        if i in string.digits:
            digit.append(i)
        elif i in string.ascii_letters:
            letter.append(i)
        elif i in string.punctuation or i.isspace():
            punctuation.append(i)
        else:
            chinese.append(i)
        print('数字：{}'.format(''.join(digit)))
        print('拼音：{}'.format(''.join(letter)))
        print('符号：{}'.format(''.join(punctuation)))
        print('中文：{}'.format(''.join(chinese)))

import re
def analysis(str):
    ze={"数字":"\\d","拼音":"[a-zA-Z]","汉字":"[\u4e00-\u9fff]"}
    for k,v in ze.items():
        jg=re.findall(v,str)
        print(k + ":" + ''.join(jg))
        str=re.sub(v,'',str)
        print('符号：{0}'.format(str))