一日一技：如何判断n对数字是否完全相等？

if (a == x and b == y and c == z) or (a == x and b == z and c == y) or (a == y and b == x and c == z) or (a == y and b == z and c == x) or (a == z and b == y and c == z) or (a == z and b == z and c == y):
    print('abc与xyz相等！')

if (a, b, c) == (x, y, z) or (a, b, c) == (x, z, y) or (a, b, c) == (y, x, z) or (a, b, c) == (y, z, x) or (a, b, c) == (z, x, y) or (a, b, c) == (z, y, x):
    print('abc与xyz相等！')

if (a, b, c) in {(x, y, z), (x, z, y), (y, x, z), (y, z, x), (z, x, y), (z, y, x)}:
    print('abc与xyz相等！')

from itertools import permutations

if (a, b, c) in permutations([x, y, z]):
    print('abc与xyz相等')

if {a, b, c} == {x, y, z}:
    print('abc与xyz相等')